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2 years ago

15

Find the distance between the points p1 (2,-5) And p2 (-4,3)

2 answers:

Art [367]2 years ago

8 0

It’s actually 10, you would have to use the distance formula.

jekas [21]2 years ago

4 0

(6,8) i think that is the correct answer.

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Someone explain and help pls

jasenka [17]

Your answer for the girls in the gymnastics club is correct.

Do the percentage of water the same way: Divide 139 by 197.
That'll give you the decimal amount that's covered by water.
To change the decimal to a percentage, move the decimal point
two places that way ==> .

7 0

2 years ago

Find the dicontinuities of the function. f(x) = x2 + 12x + 27 x2 + 4x + 3 . There is a removable discontinuity at (, ).

ValentinkaMS [17]

Solution-

$f(x)=\frac{x^{2}+12x+27 }{x^{2} +4x+3} =\frac{x^{2}+9x+3x+27 }{x^{2} +3x+x+3}=\frac{(x+3)(x+9)}{(x+3)(x+1)}$

Equating the denominator to 0,

⇒ (x+3)(x+1) = 0

⇒ x= -3, -1

∴ Discontinuities of the function f(x) is at -3, -1

As (x+3) is also a factor of the numerator, you will have what's called a removable discontinuity. That will show up as a hole in the graph.

∴ At x = -3, you will have removable discontinuity.

4 0

2 years ago

Read 2 more answers

For two days in a row Alvin jogged in the park he jogged for 46 min on Friday this is 19 min less than he ran on Saturday write

Luda [366]

Saturday = 46+19 min = 65 minutes

8 0

2 years ago

Consider the equation pV=kTN , where k is a constant. Select all of the correct answers that describe the variation between vari

Mumz [18]

Answer:

See below

Step-by-step explanation:

Rule: If the variables are on the same side of the equal sign, they vary INVERSELY.

If the variables are on the opposite side of the equal Sign, they very DIRECTLY.

a) T and V

Opposite sides
Directly

b) p and T

Opposite Sides
Directly

c) N and V

Opposite Sides
Directly

d) N and T

Same Side
Inversely

e) p and N

Opposite Sides
Directly

f) V and P

Same Side
Inversely.

4 0

2 years ago

Find the sum of the first 63 terms of –19, -13, -7 …

boyakko [2]

The Given Sequence is an Arithmetic Sequence with First term = -19

⇒ a = -19

Second term is -13

We know that Common difference is Difference of second term and first term.

⇒ Common Difference (d) = -13 + 19 = 6

We know that Sum of n terms is given by : $S_n = \frac{n}{2}(2a + (n - 1)d)$

Given n = 63 and we found a = -19 and d = 6

$\implies S_6_3 = \frac{63}{2}(2(-19) + (63 - 1)6)$

$\implies S_6_3 = \frac{63}{2}(-38 + (62)6)$

$\implies S_6_3 = \frac{63}{2}(-38 + 372)$

$\implies S_6_3 = \frac{63}{2}(-38 + 372)$

$\implies S_6_3 = \frac{63}{2}(334)$

$\implies S_6_3 = {63}(167) = 10521$

The Sum of First 63 terms is 10521

4 0

2 years ago