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IRISSAK [1]
2 years ago
11

A function f on [a, b] is called a step function if there exists a partition P = {a = u0 < u1 < ··· < cm = b} of [a, b]

such that f is constant on each interval (uj−1, uj ), say f(x) = cj for x in (uj−1, uj ). (a) Show that a step function f is integrable and evaluate " b a f.
Mathematics
1 answer:
Arturiano [62]2 years ago
3 0

Answer:

IDK

Step-by-step explanation:

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Choose the correct item from each drop-down menu to factor the trinomial 6y2 + 19y + 15 by grouping.
Alex73 [517]

Answer: (3y - 5) • (2y - 3)

Step-by-step explanation:      6y2 - 10y - 9y - 15

2.1     Factoring  6y2-19y+15

The first term is,  6y2  its coefficient is  6 .

The middle term is,  -19y  its coefficient is  -19 .

The last term, "the constant", is  +15

5 0
2 years ago
Two boats leave port at noon. Boat 1 sails due east at 12 knots. Boat 2 sails due south at 8 knots. At 2 pm the wind diminishes
Ivan

Answer:

14.86 knots.

Step-by-step explanation:

<em>Given that:</em>

The boats leave the port at noon.

Speed of boat 1 = 12 knots due east

Speed of boat 2 = 8 knots due south

At 2 pm:

Distance traveled by boat 1 = 24 units due east

Distance traveled by boat 2 = 16 units due south

Now, speed of boat 1 changes to 9 knots:

At 3 pm:

Distance traveled by boat 1 = 24 + 9= 33 units due east

Distance traveled by boat 2 = 16+8 = 24 units due south

Now, speed of boat 1 changes to 8+7 = 15 knots

At 5 pm:

Distance traveled by boat 1 = 33 + 2\times 9= 51 units due east

Distance traveled by boat 2 = 24 + 2 \times 15 = 54 units due south

Now, the situation of distance traveled can be seen by the attached right angled \triangle AOB.

O is the port and A is the location of boat 1

B is the location of boat 2.

Using pythagorean theorem:

\text{Hypotenuse}^{2} = \text{Base}^{2} + \text{Perpendicular}^{2}\\\Rightarrow AB^{2} = OA^{2} + OB^{2}\\\Rightarrow AB^{2} = 51^{2} + 54^{2}\\\Rightarrow AB^{2} = 2601+ 2916 = 5517\\\Rightarrow AB = 74.28\ units

so, the total distance between the two boats is 74.28 units.

Change in distance per hour = \dfrac{Total\ distance}{Total\ time}

\Rightarrow \dfrac{74.28}{5} = 14.86\ knots

6 0
2 years ago
Shane and Abha earned a team badge that required their team to collect no less than 2000 cans for recycling. Abha collected 178
Katarina [22]

Answer:

2x+178\geq 2000

Step-by-step explanation:

Let, the number of cans collected by Shane = x.

So, the number of cans collected by Abha = x + 178.

Since, at least 2000 cans are required to be collected.

Thus, we have the inequality,

Number of cans by Shane + Number of cans by Abha ≥ 2000.

i.e. x+(x+178)\geq 2000

i.e. 2x+178\geq 2000

Thus, the required inequality is 2x+178\geq 2000.

4 0
2 years ago
The image of ΔABC after a reflection across Line E G is ΔA'B'C'. 2 triangles are shown. A line of reflection is between the 2 tr
nirvana33 [79]

Answer:  

It's A - F is the midpoint of AA' because Line E G bisects AA'

Step-by-step explanation: :D

6 0
2 years ago
Read 2 more answers
Help!
Leona [35]

Step-by-step explanation:

first minute = 24 wildebeest

by 20 min = (20 × 3) + 24 = 84 wildebeest

3 0
2 years ago
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