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Ilia_Sergeevich [38]
2 years ago
10

Your marketing agency wants to send a survey to 500 people. You desire the respondents to represent the full range of incomes un

der $100,000 per year. You are authorized to purchase 500 names chosen at random from 1 of the following 3 databases. Which database is most likely to fit your needs, and why? Income distribution Database 1 Database 2 Database 3 Mean $25,625 $49,205 $88,340 Standard deviation $15,990 $25,485 $35,870 Database 1, because its mean is farthest from the limit of $100,000 Database 1, because its standard deviation is smallest and so the data are most focused Database 2, because its mean is centered between $0 and $100,000 Database 3, because its mean is closest to $100,000 Database 3, because its standard deviation is largest
Mathematics
2 answers:
Ede4ka [16]2 years ago
7 0

Answer:

Database 2  is most likely to fit needs as it has maximum % of people lying in Range and mean is centered

kakasveta [241]2 years ago
5 0

Answer:

Database 2, because its mean is centered between $0 and $100,000

Step-by-step explanation:

You desire the respondents to represent the full range of incomes under $100,000 per year. Then, database 2 is the one best fit this criteria, because is centered between $0 and $100,000, so there are more chances to select people from here which satisfy the desired criteria. In database 1 there are few people with salaries near $100,000, and in database 3  there are few people with salaries near $0

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A decimal outline is an outline that uses notations such as 1.1, 1.2, and 1.3. The second outline is Roman numerals while the third is Letter notation.
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A control chart is developed to monitor the analysis of iron levels in human blood. The lines on the control chart were obtained
sergejj [24]

Answer:

Step-by-step explanation:

Hello!

The variable is X: iron level on human blood.

It has a mean of μ= 51.50 mg/dl and a standard deviation of σ= 3.50 mg/dl.

According to the control chart, the process should be shut down for troubleshooting when the analysis shows values X[bar]≥ 53.42 mg/dl and X[bar]≤ 49.58 mg/dl

Warnings are received at levels X[bar]≥52.78 mg/dl and X[bar]≤ 50.22 mg/dl

The system works between levels 49.58<X[bar]<53.42 and works without warnings between 50.22<X[bar]<52.78.

Using these parameters you have to analyze if the lists of sample means to see which ones are within the working values are wich ones are outside this interval.

<u>Sample 1</u>

Min= 50.15

Max= 51.99

Mean= 51.61

Without warning 50.22<X[bar]<52.78

Without Action interval 49.58<X[bar]<53.42

<em>This sample's min value is below the lower limit of the warning interval but not low enough to reach action levels, the max value is within the working range.</em>

<em><u /></em>

<u>Sample 2 </u>

Min= 50.32

Max= 52.56

Mean= 51.16

Without warning 50.22<X[bar]<52.78

Without Action interval 49.58<X[bar]<53.42

<em>Both the max and min values of the sample are within the working range without warning.</em>

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<u>Sample 3</u>

Min= 50.25

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Mean= 51.83

Without warning 50.22<X[bar]<52.78

Without Action interval 49.58<X[bar]<53.42

<em>The max value of this sample is above the upper limit of the warning interval but does not surpass the upper bond of the troubleshoot interval. Min value is within working values.</em>

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<u>Sample 4</u>

Min= 50.05

Max= 53.01

Mean= 51.70

Without warning 50.22<X[bar]<52.78

Without Action interval 49.58<X[bar]<53.42

<em>Both min and max values surpass the warning interval but do not reach action levels</em>.

<u>Sample 5</u>

Min= 50.35

Max= 52.71

Mean= 51.37

Without warning 50.22<X[bar]<52.78

Without Action interval 49.58<X[bar]<53.42

<em>Both min and max values are within working levels without warnings.</em>

<em />

Considering that samples reaching warning levels should be shut down as a precaution, they are classified as:

Shutdown: Sample 1, 3 and 4

Do not shutdown: Sample 2 and 5.

I hope it helps!

8 0
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A blogger had 400 subscribers to her blog in January. The number of subscribers has grown by a factor of 1.5 every month since t
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Amina used the quadratic formula to solve an equation. Her result shows two solutions that are complex numbers with imaginary pa
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Answer:

3rd graph down

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