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-Dominant- [34]
1 year ago
12

A daycare center charges a $75 enrollment fee plus $100 per week. Which of the following represents the cost of sending a child

to daycare for 14 weeks?
Mathematics
2 answers:
nika2105 [10]1 year ago
5 0

Answer:

$1475

Step-by-step explanation:

One week costs $100.

Note that:

The $75 enrollment fee is a one-time payment.

$100 per week is the amount that is paid per week, and can change depending on the amount of week they pay for.

In this case, the child would be there for 14 weeks. Set the equation. Let x = amount of weeks, and t = total cost:

100x + 75 = t

We know that the child will be there for 14 weeks, so plug in 14 for x.

(100)(14) + 75 = t

t = (100 * 14) + 75

Simplify. Remember to follow PEMDAS. Multiply first, then add:

t = (1400) + 75

t = 1475

The total cost for 14 weeks is $1475.

~

Lorico [155]1 year ago
3 0

Answer:

$1,475

Step-by-step explanation:

times 100 by 14 which is 1400

but then add 75 onto that

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A circular pond is to be surrounded by a gravel path. Use the diagram to find the square feet of gravel needed if we know the po
kiruha [24]
I think the correct answer is 70,650 ft², but I would make sure with someone else just in case. 

Hope this helps!

4 0
1 year ago
Read 2 more answers
Two cones are similar. The surface area of the larger cone is 65π square inches. The surface area of the smaller cone is 41.6π s
devlian [24]

Answer:

8 inches

Step-by-step explanation:

The surface area of a cone (without the base) is given by:

Surface area = pi*r*s

Where r is the base radius and s is the slant height.

The smaller cone has a surface area of 41.6pi in2 and a radius of 6.4 inches, so the slant height is:

41.6pi = pi*r*s

41.6 = 6.4s

s = 6.5 in

If the cones are similar, the radius and the slant height increase in the same proportion, so we have that:

r'/s' = r/s = 6.4/6.5

s' = r'*6.5/6.4

So for the larger cone, we have:

65pi = pi*r'*s'

65 = r'*r'*6.5/6.4

r'^2 = 64

r' = 8 inches

5 0
2 years ago
Read 2 more answers
13. En un pueblo, 5 personas escucharon una noticia. En una hora, cada una de ellas
Vera_Pavlovna [14]

Answer:

En 5 horas se habrá enterado todo el pueblo.

Step-by-step explanation:

Sabemos que en un pueblo 5 personas escucharon una noticia.

Una hora más tarde, cada una de ellas le contó la noticia a otras 5.

Luego, éstas contaron la noticia a otras 5 y así sucesivamente.

Nadie cuenta ni escucha la noticia más de una vez y en ese pueblo hay un poco más de 19000 habitantes.

La ecuación a desarrollar para resolver el problema es la siguiente :

Comenzamos con 5 personas que escucharon la noticia a la ''hora 0''.

Una hora más tarde, cada una de ellas le contó a 5 personas, es decir , pasada la primera hora tendremos :

5+5^{2}=30 (I)

Las 5 personas originales de la ''hora 0'' más 25 personas que se enteraron pasada la primera hora. La ecuación que planteamos es la siguiente :

5^{1}+5^{2}+5^{3}+...+5^{x}>19000 (II)

Buscamos el valor de x que satisface la ecuación (II).

Probando y realizando las sumas encontramos que :

5^{1}+5^{2}+5^{3}+5^{4}+5^{5}+5^{6}>19000

19530>19000

El valor de x que satisface (II) es x=6.

Para hallar el número de horas nos fijamos que en (I) el valor del mayor exponente del 5 es el número 2. Para ese valor 2, el tiempo que pasó es una hora.

Entonces para nuestro x=6, el número de horas que pasaron son 5 horas (1 menos que el valor de x)

Todo el pueblo se habrá enterado en 5 horas de la noticia.

7 0
2 years ago
The aquarium at Sea Critters Depot contains 140 fish. Eighty of these fish are green swordtails (44 female and 36 male) and 60 a
maxonik [38]

Given that:

Total number of fish = 140

Fish are green swordtails female = 44

Fish are green swordtails male = 36

Fish are orange swordtails female = 36

Fish are orange swordtails male = 24

Solution:

A. We have to find the probability that the selected fish is a green swordtail.

\text{P(green swordtail)}=\dfrac{\text{Total green swordtail fish}}{\text{Total fish}}

\text{P(green swordtail)}=\dfrac{80}{140}

\text{P(green swordtail)}=\dfrac{4}{7}

Therefore, the probability that the selected fish is a green swordtail is \dfrac{4}{7}.

B.  We have to find the probability that the selected fish is male.

\text{P(Male fish)}=\dfrac{\text{Total male fish}}{\text{Total fish}}

\text{P(Male fish)}=\dfrac{36+24}{140}

\text{P(Male fish)}=\dfrac{60}{140}

\text{P(Male fish)}=\dfrac{3}{7}

Therefore, the probability that the selected fish is a male, is \dfrac{3}{7}.

C. We have to find the probability that the selected fish is a male green swordtail.

\text{P(Male green swordtail)}=\dfrac{\text{Total male green swordtail fish}}{\text{Total fish}}

\text{P(Male green swordtail)}=\dfrac{36}{140}

\text{P(Male green swordtail)}=\dfrac{9}{35}

Therefore, probability that the selected fish is a male green swordtail is \dfrac{9}{35}.

D.

We have to find the probability that the selected fish is either a male or a green swordtail.

\text{P(Male or green swordtail)}=\dfrac{\text{Total male or green swordtail fish}}{\text{Total fish}}

\text{P(Male or green swordtail)}=\dfrac{44+36+24}{140}

\text{P(Male or green swordtail)}=\dfrac{96}{140}

\text{P(Male or green swordtail)}=\dfrac{24}{35}

Therefore, the probability the selected fish is either a male or a green swordtail is \dfrac{24}{35}.

4 0
1 year ago
Help with this question quickly please!!
DiKsa [7]

Answer:

The anwers is D

Step-by-step explanation:

8 0
1 year ago
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