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2 years ago

Which equation has the solutions x = 5+/- 2 the squire root of 7 over 3

1 answer:

5 0

If you look at the quadratic formula:

x=(-b±√(b^2-4ac))/(2a)

We can say that -b=5, b=-5

If I read it right you had ±2√7 which is equal to ±√28, and we know b=-5 so:

±√(25-4ac)=±√28

And since 3=2a, a=1.5 making the above:

±√(25-6c)=±√28

25-6c=28

-6c=3

c=-0.5

So a=1.5, b=-5, and c=-0.5 thus

y=1.5x^2-5x-0.5

We can check this by reapplying the quadratic formula to the equation above

x=(5±√(25-4(1.5)(-0.5))/3

x=(5±√(25+3))/3

x=(5±√28)/3

x=(5±√(4*7))/3

x=(5±2√7)/3

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Margaret and Bethany have a lemonade stand for one week each summer.

Monica [59]

Answer:

6.00

Step-by-step explanation:

5 0

2 years ago

Isaac keeps track of the miles per gallon his car gets per week. He has accumulated the following data:

ipn [44]

we know that

A <u>geometric sequence</u> is a sequence of numbers in which the ratio between consecutive terms is constant

Let

$a1=24 \ a2=24.48\ a3=24.97\ a4=25.47$

$\frac{a2}{a1} = \frac{24.48}{24}= 1.02$

$a2=a1*1.02$

$\frac{a3}{a2} = \frac{24.97}{24.48}= 1.02$

$a3=a2*1.02$

$\frac{a4}{a3} = \frac{25.47}{24.97}= 1.02$

$a4=a3*1.02$

therefore

The common ratio is equal to $1.02$

<u>the answer is</u>

The common ratio is 1.02

4 0

2 years ago

Read 2 more answers

An automated egg carton loader has a 1% probability of cracking an egg, and a customer will complain if more than one egg per do

vaieri [72.5K]

Answer:

a) Binomial distribution B(n=12,p=0.01)

b) P=0.007

c) P=0.999924

d) P=0.366

Step-by-step explanation:

a) The distribution of cracked eggs per dozen should be a binomial distribution B(12,0.01), as it can model 12 independent events.

b) To calculate the probability of having a carton of dozen eggs with more than one cracked egg, we will first calculate the probabilities of having zero or one cracked egg.

$P(k=0)=\binom{12}{0}p^0(1-p)^{12}=1*1*0.99^{12}=1*0.886=0.886\\\\P(k=1)=\binom{12}{1}p^1(1-p)^{11}=12*0.01*0.99^{11}=12*0.01*0.895=0.107$

Then,

$P(k>1)=1-(P(k=0)+P(k=1))=1-(0.886+0.107)=1-0.993=0.007$

c) In this case, the distribution is B(1200,0.01)

$P(k=0)=\binom{1200}{0}p^0(1-p)^{12}=1*1*0.99^{1200}=1* 0.000006 = 0.000006 \\\\ P(k=1)=\binom{1200}{1}p^1(1-p)^{1199}=1200*0.01*0.99^{1199}=1200*0.01* 0.000006 \\\\P(k=1)= 0.00007\\\\\\P(k\leq1)=0.000006+0.000070=0.000076\\\\\\P(k>1)=1-P(k\leq 1)=1-0.000076=0.999924$

d) In this case, the distribution is B(100,0.01)

We can calculate this probability as the probability of having 0 cracked eggs in a batch of 100 eggs.

$P(k=0)=\binom{100}{0}p^0(1-p)^{100}=0.99^{100}=0.366$

5 0

2 years ago

Gus has skydived four more times than Niko Emma has skydive twice as many times as Nico if Emma has skydived 16 times, how many

ad-work [718]

Answer: Gus skydived 32 times

Step-by-step explanation:

G = number of times that Gus skydives

N = number of times that Nico skydives

E= number of times that Emma skydives

Gus skydives 4 times as much as Nick

This means G = 4N

Emma skydives 2 times as much as Nick.

This means E= 2N

If Emma has skydived 16 times,

That means E = 16

Put E = 16 in E= 2N,

16 =2N

N= 16/2 = 8

Put N= 8 in G = 4N

G =4×8 = 32

Gus skydived 32 times

Check

Nick skydived 8 times

Emma skydived 16 times

3 0

2 years ago

Dominic runs a farm stand that sells peaches and grapes yesterday Dominic sold 34 pounds of peaches and 45 lb of grapes for a to

iren2701 [21]

Answer:34p+16g=208

47p+16g=208

Step-by-step explanation:

Let p=the price of each pound of peaches.

Let g=the price of each pound of grapes.

Each pound of peaches sells for $p, so 34 pounds of peaches will bring in 34p dollars. Each pound of grapes will bring in 45g dollars. Therefore, the total amount 34p+45g=192.25

Likewise, if 47 pounds of peaches and 16 pounds of grapes brought in $208 then

47p+16g=208

34p+45g=192.25

47+16g=208

3 0

2 years ago