Answer: 30
Step-by-step explanation:
Given :The weight of a bag of golf balls varies directly as the number of golf balls in the bag.
Let x be the number of golf balls in a bag that weighs 1,110 grams.
Then we have the following direct variation equation,
Multiply 1110 both sides , we get
Hence, there are 30 balls in the bag.
Start with how much profit they are making off each race entry. People pay $55 to race, but $15 of that is expenses so they are only profiting $40 for each entry. Now write one side of the equality. They start with $10,000 in donations, and then have a $40 profit for each race entry. So 10,000+40x. X will represent the unknown number of race entries. What do we want that expression to be equal to? We want 10000+40x>55000. It can also be greater than or equal to, not just greater than.
Solve for x. Subtract 10000 from each side resulting in 40x>45000. Divide each side by 40 to solve for x. X>1125. X needs to bbe greater than or equal to 1125. If there are 1125 race entries, the charity will profit exactly $55000, so the lowest number of race entries is 1125
The roots of the polynomial <span><span>x^3 </span>− 2<span>x^2 </span>− 4x + 2</span> are:
<span><span>x1 </span>= 0.42801</span>
<span><span>x2 </span>= −1.51414</span>
<span><span>x3 </span>= 3.08613</span>
x1 and x2 are in the desired interval [-2, 2]
f'(x) = 3x^2 - 4x - 4
so we have:
3x^2 - 4x - 4 = 0
<span>x = ( 4 +- </span><span>√(16 + 48) </span>)/6
x_1 = -4/6 = -0.66
x_ 2 = 2
According to Rolle's theorem, we have one point in between:
x1 = 0.42801 and x2 = −1.51414
where f'(x) = 0, and that is <span>x_1 = -0.66</span>
so we see that Rolle's theorem holds in our function.
Answer:
a=√2
Step-by-step explanation:
Given : ΔEGF ≅ ΔHKJ
where ∠G=∠K [right angle]
∠E=∠H=45°
And ∠F=180°-∠E-∠G [By angle sum property]
⇒∠F=180°-45°-90°
⇒∠F=45°=∠J [corresponding parts of two congruent triangles are congruent]
⇒ Both triangles are isosceles right triangles such that
JK=HK=b , EG=GF
and EF=JH
Now JK=HK= EG=GF=3√2
Now GF=3a=3√2
⇒a=√2
