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morpeh [17]
1 year ago
15

The histogram to the right represents the weights​ (in pounds) of members of a certain​ high-school programming team. What is th

e class​ width? What are the approximate lower and upper class limits of the first​ class? 100 120 140 160 180 200 220 240 0 1 2 3 4 5 6 Weight (lbs) Frequency A histogram with horizontal axis labeled "Weight (pounds)" from 100 to 240 in intervals of 20 and vertical axis labeled "Frequency" from 0 to 6 in intervals of 1 contains seven adjacent vertical bars with heights as follows: 100 to 120, 4; 120 to 140, 1; 140 to 160, 1; 160 to 180, 3; 180 to 200, 3; 200 to 220, 4; 220 to 240, 2. What is the class​ width? The class width is nothing. ​(Simplify your​ answer.) What are the approximate lower and upper class limits of the first​ class? The approximate lower class limit is nothing. The approximate upper class limit is nothing. ​(Simplify your​ answers.)
Mathematics
1 answer:
AVprozaik [17]1 year ago
4 0

Answer:

Class width=20

Lower class limit of first class=100

Upper class limit of first class=120

Step-by-step explanation:

The class width can be calculated by taking the difference of two consecutive upper class limits or lower class limits.

Now we take any two consecutive upper class limits or lower class limits from classes 100-120,120-140,140-160,160-180,180-200,200-220,220-240.

We take upper class limits of first and second class i.e. 100 and 120.

Class width=120-100=20

Class width=20

The approximate lower and upper class limits of the first class from classes  100-120,120-140,140-160,160-180,180-200,200-220,220-240 are 100 and 120.

Class limits for first class is 100-120.

Lower class limit of first class=100

Upper class limit of first class=120

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Which expression is equivalent to ( xy -6)2 for all values of x and y where the expression is defined?
hichkok12 [17]

Answer:

 ( x y -6)²  =  x² y² - 12 xy + 36            

Step-by-step explanation:

<u><em>Explanation:-</em></u>

Given that the expression ( x y -6)²

Apply formula (a-b)² = a² -2ab + b²

( x y -6)² = (xy)² - 2 × xy× 6 + (6)²

             = x² y² - 12 xy + 36

( x y -6)²  =  x² y² - 12 xy + 36            

4 0
1 year ago
Read 2 more answers
Pecans that cost $28.50 per kilogram were mixed with almonds that cost $22.25 per kilogram. How many kilograms of each were used
atroni [7]

Answer:

The pecans used in the mixture =  8 kg

The almonds used in the mixture  =  17 kg

Step-by-step explanation:

The cost of per kg of pecans  = $28.50

The cost of per kg of almonds = $22.25

Now, total weight of mixture  = 25 kg

Let us assume the weight of pecans in the mixture   =   m kg

So, the amount of almonds in the mixture  = Total weight - Weight of Pecans

= (25 - m) kg

Now, cost of m kg pecans  = m x ( cost of 1 kg pecans) = m x ( $ 28.50)

                                              =  28.50 m

cost of (25- m) kg almonds  = (25 -m)  x ( cost of 1 kg almonds)

                                                = (25 - m) x ( $ 22.25)

                                                =  556.25  - 22.25 m

Total cost  of 25 kg of mixture  = 25 x ( $24.25) =  $606.25

Now, Total Cost of (almonds  + Pecans)  = Total cost of mixture

⇒28.50 m + 556.25  - 22.25 m  = $606.25

or,6.25 m =  50

or, m = 50/6.25 =  8

Hence, the pecans used in the mixture = m = 8 kg

And the  almonds used in the mixture  = (25 - m) = 25 - 8 = 17 kg

5 0
1 year ago
Lynn is making custom bricks. She combines 39 pounds of water and 48 pounds of brick dust in a mixing bucket. She spills 13 poun
ehidna [41]

Lynn mixes 39 pounds of water with 48 pounds of brick dust, so the mixture has a total weight of 39 + 48 = 87 pounds.

13 pounds are spilled during mixing, so she's left with 87 - 13 = 74 pounds to turn into bricks.

7 pounds are needed for 1 brick, so she can make 10 bricks because 7 • 10 = 70 and 7 • 11 = 77, and 70 < 74 < 77.

If she uses the mixture to make 10 bricks, she uses up 70 pounds of it, which leaves 4 pounds to be washed out.

5 0
1 year ago
Keenan currently does a total of 888 pushups each day. He plans to increase the number of pushups he does each day by 222 pushup
marishachu [46]

Answer:

8 + 2x = 30

Step-by-step explanation:

Given,

The initial number of push-ups he does in each day = 8,

And, the number of push-ups, he increases per day = 2,

Let x be the number of days after he will reach his target of 30 push-ups,

Since, the number of push-ups she will increase in x days = 2x,

Thus, the number of push-ups she will do after x days = 8 + 2x,

⇒ 8 + 2x = 30, which is the required equation.

4 0
1 year ago
An office building has two elevators. One elevator starts out on the 4th floor, 35 feet above the ground, as it’s defending at a
iren2701 [21]

The system of equations are y = 35 - 2.2x and y = 1.7x

<em><u>Solution:</u></em>

Given that, office building has two elevators.

<em><u>One elevator starts out on the 4th floor, 35 feet above the ground, as it’s descending at a rate of 2.2 feet per second</u></em>

Let "x" be the number of seconds for which the elevator is descending

Therefore, for "x" seconds the descended feet is 2.2x feet

The elevator is at 4 th floor, 35 feet above ground

Therefore, from 35 feet, the elevator has descended 2.2x feet for "x" seconds

Let "y" be the final position of elevator after "x" seconds

Therefore,

y = 35 - 2.2x

<em><u>The other elevator starts out at ground level and is rising at a rate of 1.7 feet per second</u></em>

Here, the elevator is rising at a rate of 1.7 feet per second

Therefore, for "x" seconds, the elevator has raised 1.7x feet

Here the elevator is at ground level, therefore

y = 1.7x

Thus the system of equations are y = 35 - 2.2x and y = 1.7x

6 0
1 year ago
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