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yanalaym [24]
2 years ago
10

The ratio of rabbits to guinea pigs in a shop is 2:7. The ratio of brown rabbits to grey rabbits is 2:3.What fraction of the ani

mals in the shop are grey rabbits?
Mathematics
1 answer:
Arturiano [62]2 years ago
8 0
Answer: 2/15
Explanation: 2/9 x 3/5 then simplify it
You might be interested in
A car insurance company suspects that the younger the driver is, the more reckless a driver he/she is. They take a survey and gr
erastovalidia [21]

Answer:

The confidence interval for the difference in proportions is

-0.028\leq p_1-p_2 \leq 0.096

No. As the 95% CI include both negative and positive values, no proportion is significantly different from the other to conclude there is a difference between them.

Step-by-step explanation:

We have to construct a confidence interval for the difference of proportions.

The difference in the sample proportions is:

p_1-p_2=x_1/n_1-x_2/n_2=(183/217)-(322/398)=0.843-0.809\\\\p_1-p_2=0.034

The estimated standard error is:

\sigma_{p_1-p_2}=\sqrt{\frac{p_1(1-p_1)}{n_1}+\frac{p_2(1-p_2)}{n_2} } \\\\\sigma_{p_1-p_2}=\sqrt{\frac{0.843*0.157}{217}+\frac{0.809*0.191}{398} } \\\\\sigma_{p_1-p_2}=\sqrt{0.000609912+0.000388239}=\sqrt{0.000998151} \\\\ \sigma_{p_1-p_2}=0.0316

The z-value for a 95% confidence interval is z=1.96.

Then, the lower and upper bounds are:

LL=(p_1-p_2)-z*\sigma_p=0.034-1.96*0.0316=0.034-0.062=-0.028\\\\\\UL=(p_1-p_2)+z*\sigma_p=0.034+1.96*0.0316=0.034+0.062=0.096

The confidence interval for the difference in proportions is

-0.028\leq p_1-p_2 \leq 0.096

<em>Can it be concluded that there is a difference in the proportion of drivers who wear a seat belt at all times based on age group?</em>

No. It can not be concluded that there is a difference in the proportion of drivers who wear a seat belt at all times based on age group, as the confidence interval include both positive and negative values.

This means that we are not confident that the actual difference of proportions is positive or negative. No proportion is significantly different from the other to conclude there is a difference.

8 0
2 years ago
Alex is x years old. Addison is y years younger. Find their combined age in 10 years’ time.
stira [4]

Answer:

x+10-y

Step-by-step explanation:

i'm not 100% sure about this response, but i'd assume the answer is like this for the following reasons:

alex is x years old, and 10 years have passed, meaning 10 years are added onto his age (x+10). addison is still the same amount of years apart from him in age, so you subtract y from that (x+10-y).

4 0
2 years ago
An iPhone costs £699 in London, €799 in Paris and $1,099 in New York. Using £1 = €1.13 and £1 = $1.37, state the lowest price of
Alex787 [66]

Answer:

£699 in London

£902.87 in Paris

£1505.63 in New York

The lowest price of the iPhone is £699 in London.

3 0
1 year ago
The average credit card debt for a recent year was $8,776. Five years earlier the average credit card debt was $8,189. Assume sa
Anestetic [448]

Answer:

We reject H₀.  We support that the new average credit card debt is bigger than the previous average

Step-by-step explanation:

Five years earlier

μ   = 8189

σ  =  690

Sample size   n  = 32

Recent year debt

x  =  8776

Sample size   n  = 32

a) Hypothesis Test:

Null Hypothesis                        H₀            x  =  μ   = 8189

Alternative Hypothesis           Hₐ             x >  μ

b) z(c)  Alternative Hypothesis establishes that the test is a one tail-test to the right.

z(c)   for significance level  α = 0.05    is  from z-table      z(c) = 1,64

c) z(s)  =  (  x  -   μ ) / σ /√n

z(s)  =  ( 8776  - 8189 ) / 690 /√32

z(s)  =  587 *5,66/ 690

z(s) = 4,81

d) Comparing   z(c)    and z(s)

z(s)  >  z(c)   Then z(c) is in the rejection region and we reject H₀

e) We have evidence that at 95 % of confidence the new value for the debt in credit card is now bigger than the average

7 0
1 year ago
5. Round 16.975 to the nearest hundredths
ra1l [238]

Answer:

5. B

6. C

7. D

Step-by-step explanation:

hope this is correct and helps hehe

7 0
1 year ago
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