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yKpoI14uk [10]
1 year ago
12

The average credit card debt for a recent year was $8,776. Five years earlier the average credit card debt was $8,189. Assume sa

mple sizes of 32 were used and the population standard deviations of both samples were $690. Is there evidence to cónclude that the average credit card debt has increased? Use a- 0.05
a. State the hypotheses
b. Find the critical value.
c. Compute the test statistic
d. Make the decision.
e. Summarize the results
Mathematics
1 answer:
Anestetic [448]1 year ago
7 0

Answer:

We reject H₀.  We support that the new average credit card debt is bigger than the previous average

Step-by-step explanation:

Five years earlier

μ   = 8189

σ  =  690

Sample size   n  = 32

Recent year debt

x  =  8776

Sample size   n  = 32

a) Hypothesis Test:

Null Hypothesis                        H₀            x  =  μ   = 8189

Alternative Hypothesis           Hₐ             x >  μ

b) z(c)  Alternative Hypothesis establishes that the test is a one tail-test to the right.

z(c)   for significance level  α = 0.05    is  from z-table      z(c) = 1,64

c) z(s)  =  (  x  -   μ ) / σ /√n

z(s)  =  ( 8776  - 8189 ) / 690 /√32

z(s)  =  587 *5,66/ 690

z(s) = 4,81

d) Comparing   z(c)    and z(s)

z(s)  >  z(c)   Then z(c) is in the rejection region and we reject H₀

e) We have evidence that at 95 % of confidence the new value for the debt in credit card is now bigger than the average

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Answer:  Last Option is correct.

Step-by-step explanation:

Since we have given that

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Number of tulips = 150

Number of daffodils is given by

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So, We can get the ratio of tulips to daffodils which is given by

Tulips:Daffodils\\\\150:450\\\\1:3

So, we need to choose a random sample of flowers to represent the population.

1) He can choose 50 flowers.

As there are 1:3 of tulip and daffodils flowers but if we divide 50 by 4 it will give a decimal number, so it can't represent the required thing.

2) He can choose 25 tulips and 25 daffodils

As they are divided into 1:1 so, it can't represent the 1:3 tulip to daffodils population.

3) He can choose 15 tulips and 60 daffodils

As it is divided into 1:4 inspite of 1:3.So it can't represent the required population.

4) He can choose 10 tulips and 30 daffodils.

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Hence, Last Option is correct.

4 0
1 year ago
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ln20+ln5=2lnx

ln(20x5)=lnx^2

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Hope This Helps!

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A small manufacturer constructs refrigerators. The fixed monthly cost is $200,000, and it costs $450 to produce one refrigerator
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Answer: Horizontal asymptote of c(x) is 450.

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Since we have given that

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So, Average cost function to produce x refrigerators is given by

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Horizontal asymptote of c(x) would be

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Hence, Horizontal asymptote of c(x) is 450.

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If x = 3 is a solution, (x - 3) is a factor of f(x).
2x³ + x² - 25x + 12 ÷ (x - 3) [by long division] = 2x² + 7x - 4
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Answer:

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Step-by-step explanation:

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3. Plug in the third value of the set

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4. Plug in the fourth value of the set

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5. Calculate Jenny´s mother age:

As the sum of their ages is 62 ages, we have the following equation

where

x=Jenny´s age

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Therefore Jenny's mother age is 43 years old.

pls mark me brainliest

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