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Travka [436]
2 years ago
13

When equation represents the function f(x)=(1.6)x after it has been translated 5 units up 9 units to the right?

Mathematics
2 answers:
torisob [31]2 years ago
8 0

Answer:

g(x)=(1.6)^{x-9}+5

Step-by-step explanation:

Given: f(x)=(1.6)^x

The given function is f(x)=(1.6)^x.

It is exponential function because x as power of 1.6.

For left / right shift : change in x value

  • For right x\rightarrow x-a
  • For left x\rightarrow x+a

For up / down shift : change in f(x)

  • For up f(x)\rightarrow f(x)+a
  • For down f(x)\rightarrow f(x)-a

f(x)=(1.6)^x

Shift up 5 units

g(x)=f(x)+5

Shift 9 unit right

g(x)=f(x-9)+5

g(x)=1.6^{x-9}+5

Hence, The new function will be g(x)=(1.6)^{x-9}+5

wel2 years ago
5 0
For this question my answer would be

g(x)=(1.6)x-9+5

Hope this Helps
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Students at a high school were polled to determine the type of music they preferred. There were 1940 students who
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Answer:

students preferred alternative music

= 461/1940 ×100%=23.7%

6 0
2 years ago
Stacey has a square piece of cloth. She cuts 3 inches off of the length of the square and 3 inches off of the width. The area of
ratelena [41]

Answer:

The side length of the original square was 6 inches

Step-by-step explanation:

we know that

The area of a square is

A=b^2

where

b is the length side of the square

Let

x ---> the length of the original square

The area of the original square is

A=x^{2}\ in^2

The length of the smaller square is

b=(x-3)\ in

The area of the smaller square is

A=(x-3)^2\ in^2

The area of the smaller square is 1/4 the area of the original square

so

(x-3)^2=\frac{1}{4} x^{2}

solve for x

x^2-6x+9=\frac{1}{4} x^{2}

Multiply by 4 both sides

4x^2-24x+36=x^{2}

4x^2-x^2-24x+36=0\\3x^2-24x+36=0

Solve the quadratic equation by graphing

using a graphing tool

x=2, x=6

see the attached figure

The solution is x=6 in

Remember that the solution must be greater than 3 inches (because Stacey cuts  3 inches off of the length of the square and 3 inches off of the width)

therefore

The side length of the original square was 6 inches

3 0
2 years ago
A firm has a revenue function that can be represented by r (x)=700x-0.35x^2, where r (x) is the total revenue (in dollars) and x
Fudgin [204]

Answer:

How many units need to be sold to produce the maximum revenue? 1000 units

How many in dollars is the maximum revenue when the maximum of units are sold? $350,000

Step-by-step explanation:

We get max value of a function if we differentiate it and set it equal to 0.

We need to differentiate r(x) and set it equal to 0 and solve for x.

<u><em>That would be number of units sold to get max revenue.</em></u>

<u><em /></u>

<u>Then we take that "x" value and substitute into r(x) to get the max revenue amount.</u>

<u />

Before differentiating, we see the rules shown below:

f(x)=ax^n\\f'(x)=n*ax^{n-1}

Where

f'(x) is the differentiated function

Now, let's do the process:

r (x)=700x-0.35x^2\\r(x)=700-2*0.35x\\r(x)=700-0.7x\\0=700-0.7x\\0.7x=700\\x=1000

So, 1000 units need to be sold for max revenue

Now, substituting, we get:

r (x)=700x-0.35x^2\\r(1000)=700(1000)-0.35(1000)^2\\r(1000)=350,000

The max revenue amount is $350,000

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At the end it will be 20% interest.
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