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Slav-nsk [51]
1 year ago
10

2527=33214=81249=47321=?A)7 B)3 C)9​

Mathematics
1 answer:
tester [92]1 year ago
8 0

Answer:

c) 9

Step-by-step explanation:

7321=9

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A rectangular tank measuring 35 cm by 28 cm by 16 cm is 2/5 filled with
Alina [70]

Answer:

Amount of water left in tank = 440 cm³

Step-by-step explanation:

Given:

Sides of tank respectively = 35 cm , 28 cm , 16 cm  

Water level in tank = 2/5

Side of a cubic tank = 18 cm

Find:

Amount of water left in tank

Computation:

Volume level in rectangular tank = [2/5][35 x 28 x 16]

Volume level in rectangular tank = [2/5][15,680]

Volume level in rectangular tank = [31,360/5]

Volume level in rectangular tank = 6,272 cm³

Volume of cube = side³

Volume of cube = 18³

Volume of cube = 5,832 cm³

Amount of water left in tank = Volume level in rectangular tank - Volume of cube

Amount of water left in tank = 6,272 - 5,832

Amount of water left in tank = 440 cm³

7 0
1 year ago
Solve the given initial value problem and determine how the interval in which the solution exists depends on the initial value y
zalisa [80]

Answer:

y has a finite solution for any value y_0 ≠ 0.

Step-by-step explanation:

Given the differential equation

y' + y³ = 0

We can rewrite this as

dy/dx + y³ = 0

Multiplying through by dx

dy + y³dx = 0

Divide through by y³, we have

dy/y³ + dx = 0

dy/y³ = -dx

Integrating both sides

-1/(2y²) = - x + c

Multiplying through by -1, we have

1/(2y²) = x + C (Where C = -c)

Applying the initial condition y(0) = y_0, put x = 0, and y = y_0

1/(2y_0²) = 0 + C

C = 1/(2y_0²)

So

1/(2y²) = x + 1/(2y_0²)

2y² = 1/[x + 1/(2y_0²)]

y² = 1/[2x + 1/(y_0²)]

y = 1/[2x + 1/(y_0²)]½

This is the required solution to the initial value problem.

The interval of the solution depends on the value of y_0. There are infinitely many solutions for y_0 assumes a real number.

For y_0 = 0, the solution has an expression 1/0, which makes the solution infinite.

With this, y has a finite solution for any value y_0 ≠ 0.

8 0
2 years ago
Brant is preparing for the upcoming track season, and he wants to reduce the time of his 1-mile run. Last year, he conducted an
Ivanshal [37]

The Q30X program and the Intensity program are both effective because the average participant 1-mile run time was reduced for each program, but the Intensity program is the more effective program because it yielded a greater decrease in the average participant 1-mile run time.

5 0
2 years ago
Read 2 more answers
Diana sold 336 muffins at the bake sale.Bob sold 287 muffins.Bob estimates that he sold 50 fewer muffins than Diana.how did he e
malfutka [58]

Step-by-step explanation:

Since we have given that

Number of muffins Diana sold at the bake sale = 336

Number of muffins Bob sold at the bake sale = 287

Now, here we are using the method of estimation i.e. rounding the integers to nearest ones.

By estimation, we get

Number of muffins Diana sold at the bake sale = 340

Number of muffins Bob sold at the bake sale = 290

So,

Difference between them is given by

340-290\\=50

Hence, Bob sold 50 fewer muffins than Diana.

3 0
1 year ago
Read 2 more answers
Mr. Richard's science class is conducting a variety of experiments with projectiles and falling objects. Two groups of students
UNO [17]

Answer:

1.  Group C; 2.  Group B; 3.  Group D; 4.  Group A

Step-by-step explanation:

These equations are in the form

y=-4.9t^2+v_0t+h_0\\\text{or}\\y=-16t^2+v_0t+h_0, where v₀ is the initial velocity and h₀ is the initial height.

The first equation has no value for v₀ and a value of 19 for h₀.  This means there is no velocity, so the ball is dropped, and since the initial height is 19, it is dropped from 19 meters.  This makes it group C.

The second equation has a value of 50 for v₀ and no value for h₀.  This means the initial velocity is 50 and there is no initial height.  This makes it group B.

The third equation has no value for v₀ and a value of 50 for h₀.  This means there is no initial velocity, so the ball is being dropped, and the initial height is 50.  This makes it group D.

The fourth equation has a value of 19 for v₀ and no value for h₀.  This means the initial velocity is 19 and there is no initial height.  This makes it group A.

7 0
1 year ago
Read 2 more answers
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