1 year ago

If a 40,000g cannon ball is 35m above the Earth’s surface, how much potential energy does the cannon ball have?

Mathematics

1 answer:

ELEN [110]1 year ago

4 0

Answer:

Step-by-step explanation:

Remark

You could do this by converting the distance but the much more common way is to use kg and m.

Formula

PE = m * g * h

Givens

m = 40000 grams

m = 40000 grams * 1kg/1000 grams = 40 kg

g = 9.81

h = 35 m

Solution

PE = 40 * 9.81 * 35

PE = 13734 Joules

You might be interested in

How do i do this some one please explain

Talja [164]

Well since we already have our unit per mile.

We know that 1 mile = $3.50

And that the tow company towed the car 12 miles.

So we would have to multiply 12 by $3.50

soo..

12 x $3.50 = $42.00

So your answer is D. $42.00

4 0

1 year ago

15.6°F in 13 minutes

Scrat [10]

15.6 in 13 minutes? are you asking how it got to 15.6 in 13 minutes?

7 0

1 year ago

Read 2 more answers

Find the slope and y-intercept -2y=6(5-3x) Please show work

Montano1993 [528]

Y intercept: 0,-15 or just -15
Slope: 9

4 0

1 year ago

Mrs. Epps buys 500 bags of balloons for the high school prom for $250. What is the cost per bag?

Andrej [43]

.50 is the answer I think, hope this helps

7 0

1 year ago

A circle with radius of \greenD{4\,\text{cm}}4cmstart color #1fab54, 4, start text, c, m, end text, end color #1fab54 sits insid

mario62 [17]

Answer:

The area of the shaded region is $329.87\ cm^2$

Step-by-step explanation:

<u><em>The correct question is</em></u>

A circle with radius of 4cm sits inside a circle with a radius of 11cm. What is the area of the shaded region?

The shaded region is the area outside the smaller circle and inside the larger circle

we know that

To find out the shaded region subtract the area of the smaller circle from the area of the larger circle

$A=\pi r_a^{2} -\pi r_b^{2}$

simplify

$A=\pi (r_a^{2} -r_b^{2})$

where

r_a is the radius of the larger circle

r_b is the radius of the smaller circle

we have

$r_a=11\ cm\\r_b=4\ cm$

substitute

$A=\pi (11^{2} -4^{2})$

$A=\pi (105)\ cm^2$

assume

$\pi=3.1416$

substitute

$A=(3.1416)(105)=329.87\ cm^2$

7 0

2 years ago