Answer:
142 pages
Step-by-step explanation:
The parameters given are
First page of part of the book available = 143
The last is numbered with the digits 143
Since the book is said to have been split into two parts with, we have that one part of the book starts from the beginning, while the other part continue from the first part stops
Number on the pages on the first part = from 1 to number on the first page on the second part - 1
Hence, the part of the book available is the second part and the number of pages in the first part = 1 to 142 or 142 pages.
So the given series is "16, 06, 68, 88, __"
Count all the cyclical opening in each of these numbers. For example in 16, there is a one cyclical loop present in it(the one in 6), similarly in 06 it is two(one in zero and one in 6), going ahead, in 68 it is 3(one in 6 and two in 8).
From here on things become simple: hence, the cyclical figures in these equations written down becomes 1,2,3,4,_,3.
Let's now try solving the above sequence, going by the logical reasoning the only number that can fill in the gap should be 4.
<span>a1 = 3
an = a (n-1) +7</span>
1:104 because there are 52 cards in a deck and he already drew a king, so double the chances and get 1:104?
