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Archy [21]
2 years ago
8

A fruit stand is selling mandarin oranges for $6 for 4 pounds. A mandarin orange weighs about 2 ounces. There are 16 ounces in a

pound. At this rate, how many mandarin oranges can you buy for $9?
Mathematics
2 answers:
BartSMP [9]2 years ago
4 0

Answer: pretty sure you can buy 48 oranges

Step-by-step explanation:

barxatty [35]2 years ago
3 0
48 Oranges

$1.5 / pound
$1.5. $9
___. ____
1 ?

9/1.5 = 6

6 pounds of oranges
6 x 16 = 96
96/2 = 48

48 oranges
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What is the logarithm of the equilibrium constant, log K, at 25°C of the voltaic cell constructed from the following two half-re
sashaice [31]

Answer:

4.0921 is the logarithm of the equilibrium constant.

Step-by-step explanation:

Fe^{2+} (aq) +2e^{-}\rightarrow Fe(s); ​E​° = - 0.41 V

Ag^+(aq) + e^-\rightarrow Ag(s); E° = 0.80 V

Iron having negative value of reduction potential .So ,that means that it will loose electron easily and get oxidized.Hence, will be at anode.

E^{o}_{cell}=Reduction potential of cathode - Reduction potential of anode

E^{o}_{cell}=E^{o}_c-E^{o}_a

=0.80 V-(-0.41 V)=1.21 V

Fe^{2+} (aq) + 2e^{-}\rightarrow Fe(s); ​E​° = - 0.41 V

2Ag^+(aq) + 2e^-\rightarrow 2Ag(s); E° = 0.80 V

Net reaction: Fe(s)+2Ag^{+}\rightarrow Fe^{2+}+2Ag(s)

n = 2

To calculate equilibrium constant, we use the relation between Gibbs free energy, which is:

\Delta G^o=-nfE^o_{cell}

and,

\Delta G^o=-RT\ln K_{eq}

Equating these two equations, we get:

nfE^o_{cell}=RT\ln K_{eq}

where,

n = number of electrons transferred = 2

F = Faraday's constant = 96500 C

E^o_{cell} = standard electrode potential of the cell = 1.21 V

R = Gas constant = 8.314 J/K.mol

T = temperature of the reaction = 25^oC=[273+25]=298K

Putting values in above equation, we get:

2\times 96500\times 1.21 V=8.314\times 298\times \ln K_{eq}

\ln K_{eq}=9.3478

\log K_{eq}=\frac{9.3478}{2.303}=4.0921

4.0921 is the logarithm of the equilibrium constant.

7 0
2 years ago
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dolphi86 [110]

All we have to do here is divide 4 by 2

4 ÷ 2 = 2

Therefore, the artist can paint 2 paintings an hour making the unit rate, 2 paintings per hour.

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8 0
2 years ago
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There is little information please state more points.
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2 years ago
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A cone without a base is made from a half-circle of radius 10 cm. Determine the volume of the cone. Explain your reasoning.
DochEvi [55]

Answer:

  125π√3/3 cm³ ≈ 226.72 cm³

Step-by-step explanation:

The length of the circular edge of the half-circle is ...

  (1/2)C = (1/2)(2πr) = πr = 10π . . . . cm

This is the circumference of the circular edge of the cone, so the radius of the cone is found from ...

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  r = 5 . . . . cm

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And the cone's volume is ...

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  V = 125π√3/3 cm³ ≈ 226.72 cm³

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