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arlik [135]
2 years ago
11

Todd is training for a marathon. The following histogram summarizes the number of kilometers that he ran each day. 00 0 11 1 22

2 33 3 44 4 55 5 66 6 77 7 88 8 00 0 55 5 1010 10 1515 15 2020 20 Number of days\text{Number of days} Number of days Number of kilometers\text{Number of kilometers} Number of kilometers Based on this data, what is a reasonable estimate of the probability that Todd runs more than 15 km15\text{ km} 15 km 15, start text, space, k, m, end text tomorrow? Choose the best answer. Choose 1 answer: Choose 1 answer: (Choice A) A 213\dfrac{2}{13} 13 2 ​ start fraction, 2, divided by, 13, end fraction (Choice B) B 313\dfrac{3}{13} 13 3 ​ start fraction, 3, divided by, 13, end fraction (Choice C) C 513\dfrac{5}{13} 13 5 ​ start fraction, 5, divided by, 13, end fraction (Choice D) D 813\dfrac{8}{13} 13 8 ​ start fraction, 8, divided by, 13, end fraction Stuck?
Mathematics
1 answer:
olga2289 [7]2 years ago
5 0

Answer:

The answer is 5/13

Step-by-step explanation:

I don't have a explanation but I do know this answer is correct because i has this question on my test.

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What is the solution to log Subscript 3 Baseline (x + 12) = log Subscript 3 Baseline (5 x)
jonny [76]

I hope this helps you

6 0
2 years ago
At 11:00 a.M., there are 400 members and 150 non-members visiting a museum. After 11:00 a.M., 10 members leave every five minute
alexdok [17]

Answer:

16:27

Step-by-step explanation:

GIVEN: At 11:00\text{ A.M.}, there are 400 members and 150 non-members visiting a museum. After 11:00\text{ A.M.},  10 members leave every five minutes and 5 non-members arrive every five minutes.

TO FIND: ratio of members to non-members at 1:00\text{ P.M.}

SOLUTION:

Total number of members in museum at 11:00\text{ A.M.} =400

as after every 5 minutes 10 members leave

total number of  5 minutes interval in 2 hour =\frac{60}{5}=12

total members at  1:00\text{ P.M.}  =400-10\times24

                                                =160

Total number of non-members in museum at  11:00\text{ A.M.} =150

as after every 5 minutes 5 non-members arrive

total number of  5 minutes interval in 2 hour =\frac{60}{5}=12

total non-members at  1:00\text{ P.M.}  =150+5\times24

                                                        =270

ratio of members to non-members at   1:00\text{ P.M.}  =\frac{\text{number of members}}{\text{number of non-members}}

                                                                                  =\frac{160}{270}

                                                                                  =\frac{16}{27}

Hence the ratio of members to non-members at 1:00\text{ P.M.} is \frac{16}{27}

5 0
2 years ago
jacks tent is shaped like an isosceles triangle. the height of the tent measures 7 feet and the diagonal side measures 9 feet. f
Maru [420]

Answer:

8\sqrt{2}\ ft

Step-by-step explanation:

see the attached figure to better understand the problem

Remember that

An isosceles triangle has two equal sides and two equal interior angles

In the isosceles triangle ABC

Applying the Pythagorean Theorem

Let

b ----> the length of the tents base

9^2=7^2+(b/2)^2

(b/2)^2=9^2-7^2

(b^2/4)=32

b^2=128\\\\b=\sqrt{128}\ ft

simplify

b=8\sqrt{2}\ ft

7 0
2 years ago
Every day, Jorge buys a lottery ticket. Each ticket has a probability of of winning a prize. After six days, what is the probabi
Romashka [77]

The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

Every day, Jorge buys a lottery ticket. Each ticket has a 0.16 probability of winning a prize. After six days, what is the probability that Jorge has won at least one prize? Round your answer to four decimal places.

Answer:

The probability that Jorge has won at least one prize after six days is

P(at least 1 win) = 0.6487

Step-by-step explanation:

Every day, Jorge buys a lottery ticket which has a 0.16 chance of winning a prize.

We want to find out the probability that Jorge has won at least one prize after six days.

P(at least 1 win) = 1 - P(not winning for 6 days)

We know that the probability of winning is 0.16 then the probability of not winning is

P(not winning) = 1 - 0.16 = 0.84

For 6 days,

P(not winning for 6 days) = 0.84×0.84×0.84×0.84×0.84×0.84

P(not winning for 6 days) = 0.84⁶

P(not winning for 6 days) = 0.3513

Finally,

P(at least 1 win) = 1 - P(not winning for 6 days)

P(at least 1 win) = 1 - 0.3513

P(at least 1 win) = 0.6487

6 0
2 years ago
Robin's scores: 99, 108, 102, 107, 119
VashaNatasha [74]
<h3>The medians does'nt support the conclusion</h3>

<em><u>Solution:</u></em>

Given that,

Robin's scores: 99, 108, 102, 107, 119

Order the number from least to greatest

99, 102, 107, 108, 119

Median is the middle value of data set

Median is 107

Evelyn's scores: 125, 137, 138, 145, 145

Order the number from least to greatest

125, 137, 138, 145, 145

Medain is 138

The median of Evelyn's scores is greater than the median of Robin's

Therefore, the medians does'nt support the conclusion.

4 0
2 years ago
Read 2 more answers
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