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KonstantinChe [14]
1 year ago
7

Line segment QR is dilated to create line segment Q'R' using the dilation rule DT,1.5. Point T is the center of dilation. Line s

egment Q R is dilated to create line segment Q prime R prime. The length of R T is 6 and the length of R prime R is y. What is y, the distance between points R and R'?
Mathematics
2 answers:
velikii [3]1 year ago
5 0

Answer:

y= 3

Step-by-step explanation:

Given

RT = 6

k = 1.5 --- dilation ratio

See attachment

Required

Determine length, y

First, we calculate length R'T.

Since point T is the center of dilation, then:

R'T = k * RT

Substitute known values

R'T = 1.5 * 6

R'T = 9

y is between R'T and RT;

So:

y = R'T - RT\\

y = 9 -6

y= 3

nalin [4]1 year ago
5 0

Answer:

either 4 or 9

Step-by-step explanation:

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Answer:

16 fluid ounces=2 cups

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Step-by-step explanation:

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You are at the bottom of a mountain where the temperature is 74°F. The top of the mountain is 5500 feet above you. What is the t
mamaluj [8]

For every 1,000 feet you go up in elevation, the temperature decreases by about 3.3°F

 

Given:

Temperature at the bottom of the mountain is 74°F

The top of the mountain is 5500 feet above you

 

Change (reduction) in temperature is 3.3 X 5500 / 1000

= 18.15°F

 

Temperature at the top of the mountain is 74°F – 18.15°F

= 55.85°F

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2 years ago
An investment of $500 increases at a rate of 12.5% per year. What is the value of the investment after 30 years? Round to the ne
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Here's the equation:
0.125(500) + 500
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An oblong box has a volume equal to lwh, where l is the length, w is the width, and h is the height. If the volume is 24 cubic f
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Required:
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3 0
2 years ago
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Using the extended Euclidean algorithm, find the multiplicative inverse of a. 135 mod 61 b. 7465 mod 2464 c. 42828 mod 6407
rodikova [14]

Answer:

(a)1≡47 mod 61

(b)1≡2329 mod 2464

(c)Does not exist

Step-by-step explanation:

The operation a(mod b) has an inverse if the the two integers (a,b)

are co-prime. i.e. their g.c.d is 1.

(a)Given 135 mod 61

We first reduce it to its lowest form.

135 mod 61=13 mod 61

61=13(4)+9 ==> 9=61-13(4)

13=9(1)+4 ==> 4=13-9(1)

9=4(2)+1 ==> 1=9-4(2)

4=1(4)

Next we rewrite 1 as a linear combination of 13 and 61.

1=9-4(2)

=9-(13-9(1))2

=9(3)-13(2)

=(61-13(4))(3)-13(2)

=61(3)-13(12)-13(2)

1=61(3)-13(14)

1=61(3)+13(-14)

1≡-14 mod 61≡(-14+61)mod 61

1≡47 mod 61

(b)7465 mod 2464

Reducing it to its lowest form

7465 mod 2464=73 mod 2464

2464=73(33)+55 ==>55=2464-73(33)

73= 55(1)+18 ==> 18=73-55(1)

55=18(3)+1 ==>1=55-18(3)

18=1(18)

Rewriting 1 as a linear combination of 73 and 2464.

1=55-18(3)

=2464-73(33)-(73-55(1))(3)

=2464-73(33)-73(3)+55(3)

=2464-73(36)+55(3)

=2464-73(36)+(2464-73(33))(3)

=2464-73(36)+2464(3)-73(99)

=2464(4)-73(135)

1=2464(4)+73(-135)

Therefore:

1≡-135 mod 2464

1≡(-135+2464)mod 2464

1≡2329 mod 2464

(c)42828 mod 6407

The two numbers are not co-prime. In fact their g.c.d is 43.

Therefore their inverse does not exist.

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