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nadya68 [22]
2 years ago
9

Three pounds of squid can be purchased at the market for $18. Determine the equation and represent the function that defines the

cost of squid based on weight.
Mathematics
1 answer:
olga_2 [115]2 years ago
7 0
From the information given,

3 pounds = $18

Therefore, 1 pound = 18/3 = $6 (this can be treated as a constant of proportionality) such that,

Cost,C = 6*Weight, W (pounds)

Equation;

C = 6W, where C = Cost in $, and W = Weight in pounds.
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Janice and her dad are building a treehouse. Her dad bought a box of 155 nails for $3.10 and a box of 85 screws for $7.65. How m
Degger [83]
3.10/155= 0.02 } subtract = 0.07 more
7.65/85= 0.09 }
7 0
1 year ago
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Which statement is true about the discontinuities of the function f(x)?
Tema [17]

Answer:

There are asymptotes at x = three-halves and x = negative one-third.

Step-by-step explanation:

f(x) = (x + 1)/ (6x^2 - 7x - 3)

= (x + 1)( / (6x^2 + 2x - 9x  - 3)

= (x + 1) / (2x(3x + 1) - 3(3x + 1))

= (x + 1) / (2x - 3)(3x + 1)

Now x = 3/2 and x = -1/3 both make te denominator zero so these   are both asymptotes.

6 0
1 year ago
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If y is the circumcenter is angle STU find each measure
snow_tiger [21]

Answer:

Measures are SV=9 units., SY=14 units, YW=\sqrt75units , YW=\sqrt27units

Step-by-step explanation:

Given Y is the circumcenter of ΔSTU. we have to find the measures SV, SY, YW and YX.

As Circumcenter is equidistant from the vertices of triangle and also The circumcenter is the point at which the three perpendicular bisectors of the sides of the triangle meet.

Hence, VY, YW and YX are the perpendicular bisectors on the sides ST, TU and SU.

Given ST=18 units.

As VY is perpendicular bisector implies SV=9 units.

Also in triangle VTY

YT^{2}=VY^{2}+VT^{2}

⇒ 14^{2}=VY^{2}+9^{2}

⇒ VY^{2}=115

As vertices of triangle are equidistant from the circumcenter

⇒ SY=YT=UY=14 units

Hence, SY is 14 units

In ΔUWY, UY^{2}=YW^{2}+UW^{2}

⇒ 14^{2}=YW^2+11^{2}

⇒ YW^2=196-121=75 ⇒ YW=\sqrt75units

In ΔYXU, UY^{2}=YX^{2}+XU^{2}

⇒ 14^{2}=YX^2+13^{2}

⇒ YX^2=196-169=27 ⇒ YW=\sqrt27units

Hence, measures are SV=9 units., SY=14 units, YW=\sqrt75units , YW=\sqrt27units





4 0
1 year ago
Point G is on segment FH such that it partitions segment FH into a ratio of 2:3.Point F is located at (5, 7) and point H is loca
Margarita [4]

Answer:

G = (9.4, 9,4)

Step-by-step explanation:

The ratio is applied in the x-distance and the y-distance. The ratio is 2:3 so you have to divide the distances by 5 and 2/5 correspond to FG and 3/5 to GH

x-distance:

x2 - x1 = 16 - 5 = 11

11/5 = 2.2

y-distance:

y2 - y1 = 13 - 7 = 6

6/5 = 1.2

Point G = Point F + (2.2*2, 1.2*2)

Point G = (5, 7) + (4.4, 2.4)

= (9.4, 9.4)

8 0
2 years ago
A pharmaceutical company proposes a new drug treatment for alleviating symptoms of PMS (premenstrual syndrome). In the first sta
Akimi4 [234]

Answer:

95% confidence interval for p, the true proportion of all women who will find success with this new treatment is [0.238 , 0.762].

Step-by-step explanation:

We are given that a pharmaceutical company proposes a new drug treatment for alleviating symptoms of PMS (premenstrual syndrome).

In the first stages of a clinical trial, it was successful for 7 out of the 14 women.

Firstly, the pivotal quantity for 95% confidence interval for the true proportion is given by;

                             P.Q. = \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion of women who find success with this new treatment = \frac{7}{14} = 0.50

          n = sample of women = 14

<em>Here for constructing 95% confidence interval we have used One-sample z proportion statistics.</em>

So, 95% confidence interval for the true proportion, p is ;

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at 2.5%

                                            level of significance are -1.96 & 1.96}  

P(-1.96 < \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } < 1.96) = 0.95

P( -1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < {\hat p-p} < 1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.95

P( \hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < p < \hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.95

<u />

<u>95% confidence interval for p</u> = [\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } , \hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }]

= [ 0.50-1.96 \times {\sqrt{\frac{0.50(1-0.50)}{14} } } , 0.50+1.96 \times {\sqrt{\frac{0.50(1-0.50)}{14} } } ]

 = [0.238 , 0.762]

Therefore, 95% confidence interval for p, the true proportion of all women who will find success with this new treatment is [0.238 , 0.762].

4 0
2 years ago
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