Width = x
Length = x+18
Assuming the table is rectangular:
Area = x(x + 18)
Therefore:
x(x + 18) <span>≤ 175
x^2 + 18x </span><span>≤ 175
Using completing the square method:
x^2 + 18x + 81 </span><span>≤ 175 + 81
(x + 9)^2 </span><span>≤ 256
|x + 9| </span><span>≤ sqrt(256)
|x + 9| </span><span>≤ +-16
-16 </span>≤ x + 9 <span>≤ 16
</span>-16 - 9 ≤ x <span>≤ 16 - 9
</span>-25 ≤ x <span>≤ 7
</span><span>
But x > 0 (there are no negative measurements):
</span><span>
Therefore, the interval 0 < x </span><span>≤ 7 represents the possible widths.</span><span>
</span>
Answer:
Commitment Adherence Percentage = 81.
%
Step-by-step explanation:
The time period Amy scheduled herself, t = 8 a.m. - 1 p.m. from Sunday through Wednesday
The period she released her interval = 11 a. m. - 1 p.m.
Commitment Adherence Percentage = Service Minutes/(Posted Minutes + Released Lockdown Minutes) × 100
Posted minutes = 5 hours/day × 60 minutes × 4 days = 1200 minutes
Serviced minute = 5 hours/day × 60 minutes × 3 days + 3 hours × 60 minutes/hour = 1,080 minutes
Released minutes = 2 hours × 60 minutes/hour = 120 minutes
Commitment Adherence Percentage = (1,080/(1,200 + 120)) × 100 = 81.%
Yes. x=3 and y =9 are the solutions.
Because if you change x=3 and y =9 ,you will have
3+2* 9 =21
3+18 =21
21 =21 (true)
(a) there are 8C2 = 28 ways of picking 2 girls from 8
And there are 21C4 = 5985 ways of picking 4 boys
Required number of ways for 2g / 4b = 28 * 5985 = 167,580
(b) at least 2 girls means combinations of 2g/4b , 3g,3b , 4g/2b , 5g 1b or
6 girls.
2g/4b = 167,580 ways
3g/3b = 8C3 * 21C3 = 56 * 1330 = 74,480
4g/2b = 8C4* 21C2 = 70 * 210 = 14,700
5g 1b = 8C5* 21 = 56*21 = 1176
6 girls = 8C6 = 28
adding these up we get the answer to (b) which is 257,964
But how many laps did she walk
