Answer: The field F has a continuous partial derivative on R.
Step-by-step explanation:
For the field F has a continuous partial derivative on R, fxy must be equal to fyx and since our field F is ∇f,
∇f = fxi + fyj + fzk.
Comparing the field F to ∇f since they at equal, P = fx, Q = fy and R = fz
Since P is fx therefore;
∂P ∂y = ∂ ∂y( ∂f ∂x) = ∂2f ∂y∂x
Similarly,
Since Q is fy therefore;
∂Q ∂x = ∂ ∂x( ∂f ∂y) = ∂2f ∂x∂y
Which shows that ∂P ∂y = ∂Q ∂x
The same is also true for the remaining conditions given
Answer
The answer will be 66600
P.S i hope i'm right i am only in 5th grade and i do not know if this is adding and subtracting
They should charge $40 per membership, and they will make a maximum revenue of $2400
Complete question :
En un concesionario de coches hay modelos de varios colores. Los rojos suponen 1/6 del total, los azules, 2/9 del total, y los blancos, 4/15 del total.
a)¿Cuál de esos colores es el más frecuente?
b) Si hay 40 coches azules, ¿cuántos hay en total?
Responder:
Coches blancos
180 coches
Explicación paso a paso:
Dado que:
Rojo = 1/6 del total
Azul = 2/9 del total
Blanco = 4/15 del total
Para determinar qué color es el más alto, convierta los valores en decimal:
1/6 = 0,166667
2/9 = 0,2222
15/4 = 0,26667
Por lo tanto;
4/15> 2/9> 1/6
Por tanto, los coches blancos son los que más
2.)
Sea Número total = x
Por lo tanto,
2/9 de x = 40
2x / 9 = 40
2x = 360
x = 180
Por tanto, hay 180 coches en total.
100 tickets were sold.
The total amount of the tickets sold is = 5 * 100 = $500.
First prize given = $100
Second prize worth = $20 * 5 = $100
Total worth of prize + $100 + $100 = $200.
Net amount of tickets sold = $500 - $200 = $300
Expected price of each ticket sold = $300/100 = 3.
Therefore, the real price of each ticket sold is $3.
