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Anit [1.1K]
2 years ago
10

Jim's work evaluating 2 (three-fifths) cubed is shown below. 2 (three-fifths) cubed = 2 (StartFraction 3 cubed Over 5 EndFractio

n) = 2 (StartFraction 3 times 3 times 3 Over 5 EndFraction) = 2 (StartFraction 27 Over 5 EndFraction) = StartFraction 54 Over 5 EndFraction Which statement best describe Jim's first error?
Mathematics
2 answers:
maksim [4K]2 years ago
8 0

Answer:

He did not apply the power of the exponent to the denominator

Step-by-step explanation:

What ever you do to the top you have to do to the bottom and he only had the exponent on the top.

Blizzard [7]2 years ago
7 0

Answer:

2(\frac{3}{5}) ^{3}=2(\frac{3^3}{5^3}) and not 2(\frac{3}{5}) ^{3}=2(\frac{3^3}{5})

Step-by-step explanation:

Jim's work evaluating 2(\frac{3}{5}) ^{3} is shown:

2(\frac{3}{5}) ^{3}=2(\frac{3^3}{5})=2(\frac{3X3X3}{5})=2(\frac{27}{5})=\frac{54}{5}

If you look at the Second step, the exponent is taken over only the numerator. It should have been taken over both the numerator and denominator as shown below.

2(\frac{3}{5}) ^{3}=2(\frac{3^3}{5^3})

The correct workings therefore is:

2(\frac{3}{5}) ^{3}=2(\frac{3^3}{5^3})=2(\frac{3X3X3}{5X5X5})=2(\frac{27}{125})=\frac{54}{125}

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2 years ago
Each locker is shaped like a rectangular prism. Which has more storage space? explain/
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2 years ago
Polygons ABCD and EFGH are similar. Find the length of EH?
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Most likely, polygon <span>ABCD</span> has sides of known lengths.
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If the above is true, we can find the scaling factor as a ratio between lengths of corresponding sides:
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