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Furkat [3]
1 year ago
12

A triangle has side lengths of (1.3k+3.5m)(1.3k+3.5m) centimeters, (4.1k-1.6n)(4.1k−1.6n) centimeters, and (9.7n+4.4m)(9.7n+4.4m

) centimeters. Which expression represents the perimeter, in centimeters, of the triangle?
Mathematics
1 answer:
Scorpion4ik [409]1 year ago
5 0

Answer:

(5.4k+7.9m+8.1n) centimeters

Step-by-step explanation:

Given the side length of a triangle;

S1 = (1.3k+3.5m) cm

S2 = (4.1k-1.6n) cm

S3 = (9.7n+4.4m) cm

Perimeter of the triangle = S1+S2 + S3

Perimeter of the triangle = (1.3k+3.5m) + (4.1k-1.6n) + (9.7n+4.4m)

Collect the like terms;

Perimeter of the triangle = 1.3k+4.1k+3.5m+4.4m-1.6n+9.7n

Perimeter of the triangle = 5.4k+7.9m+8.1n

Hence the expression that represents the perimeter of the triangle is (5.4k+7.9m+8.1n) centimeters

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1 year ago
Triangle J K L is shown. Angle J K L is a right angle. An altitude is drawn from point K to point M on side L J to form a right
kompoz [17]

Answer:

LJ=15\ units

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

Find the length side KJ

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KJ^{2}=JM^{2}+KM^{2}

we have

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substitute

KJ^{2}=3^{2}+6^{2}

KJ^{2}=45}

KJ=\sqrt{45}\ units

simplify

KJ=3\sqrt{5}\ units

step 2

Find the value of cosine of angle MJK in the right triangle JKM

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substitute the values

cos(JKM)=\frac{3}{3\sqrt{5}}

simplify

cos(JKM)=\frac{\sqrt{5}}{5} -----> equation A

step 3

Find the value of cosine of angle MJK in the right triangle JKL

cos(JKM)=KJ/LJ

we have

KJ=3\sqrt{5}\ units

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substitute the values

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Answer:

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