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Murljashka [212]
1 year ago
12

A rectangle has a perimeter of 18 inches. a new rectangle is formed by doubling the with W in tripling the length L as shown the

new rectangle has a perimeter P of 46 inches a)write and solve a system of linear equation to find the length and width of the original rectangle
b)find the length and width of the new rectangle
Mathematics
1 answer:
vladimir1956 [14]1 year ago
8 0

a) The dimensions of original rectangle are length= 5 and width= 4.

b) The dimensions of new rectangle are length= 15 and width=8.

<u>Step-by-step explanation</u>:

  • length of a rectangle = l
  • width of a rectangle = w
  • Perimeter of a rectangle = 2(l+w)

<u>Original rectangle</u> :

18 = 2(l+w)

18 = 2l + 2w ---------(1)

<u>New rectangle</u> :

46 = 2(3l+2w)

46 = 6l + 4w ---------(2)

<u>Solving the equations</u> :

Multiply (1) by 2 and subtract (2) from (1)

 4l + 4w = 36

-(<u>6l + 4w = 46</u>)

 <u>-2l        = -10</u>

l = 10/2

length = 5 inches.

Substitute l=5 in (1)

18 = 2(5)+2w

18 = 10+2w

2w = 8

w = 8/2

width = 4 inches.

length of new rectangle = 3(l) = 3\times5 = 15 inches.

width of new rectangle = 2(w) = 2\times4 = 8 inches.

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Answer:

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Step-by-step explanation:

for y=2x-1

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y2= y-3 =(2x-1)-3= 2x-4

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2) for a slope increased by 4

y3= y+ 4x = 2x-1 +4x = 6x-1

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3) for sloped divided in half. slope of y : m=2 → slope of y4=2/2 =1

y4= x-1

4) shifted up (vertical translation) of  1 unit

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Answer:

1627190

Step-by-step explanation:

(see attached for reference)

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Case 1: If the digit in the ones place is less less than 5, then the number in the tens place remains the same and replace all the digits to its right with zeros

Case 2: If the digit in the ones places is 5 or greater, then we increase the digit in the tens place and replace all the digits to its right with zeros.

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7 0
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Given:

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