Answer:
Step-by-step explanation:
Let the integer be 6 for even and 7 for odd (say)
For 6, we divide by 2, now get 3. Now we multiply by 3 and add 1 to get 10. Now since 10 is even divide by 5, now multiply by 3 and add 1 to get 16. Now divide by 2 again by 2 again by 2 again by 2 till we get rid of even numbers.
The result is 1, so multiply by 3 and add 1 we get 4 now divide 2 times by 2 to get 1, thus this result now again repeats after 2 times.
Say if we select off number 3, multiply by 3 and add 1 to get 10 now divide by 5, now repeat the same process as above for 5 until we get 1 and it gets repeated every third time.
Thus whether odd or even after some processes, we get 1 and the process again and again returns to 1.
Answer:
4
Step-by-step explanation:
The computation is shown below:
Given that
There are total number of students i.e. 48
The ratio at present is 4:1
Now the computer needed to make the ratio be 3:1
So let us assume the number of students be 4x
And, the number of computers be x
So the 4x = 48
x = 12
So the computer be 12
Now the new ratio is 3:1
Students be 3x
And, computers be x
So
3x = 48
x = 16
Now the more computer needed is
= 16 - 12
= 4
hence, this is the answer but the same is not provided in the given options
Answer:
a

b
Step-by-step explanation:
From the question we are told that
The daily demand is 
The standard deviation is 
The service probability is 
The number of chips in the inventory is 
The number of days in his monthly is 
The lead time is 
Generally the number he should order (optimal order ) is mathematically represented as

Here
is the monthly standard deviation which is mathematically evaluated as

=> 
=> 
Also z-value for the 95% service probability from the z-table is 1.96
So

=> 
For the maximum order quantity k = 0
So

=>
=>
C) 16 bc if you think about it like 25% chance you going to pull the same chip out without looking