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natka813 [3]
2 years ago
11

Jennifer has a bag of chips that contains 2 red chips and 1 black chips. If she also has a fair die, what is the probability tha

t she rolls an even number and pulls a black chip? A) 1 18 B) 1 9 C) 1 6 D) 1 3
Mathematics
2 answers:
masha68 [24]2 years ago
7 0
Hey!
First find probability of rolling even number. There are 6 numbers in total, and 3 are even: 2, 4, and 6. So the probability of rolling an even number is:
P(even) = \frac{3}{6} = \frac{1}{2}

Next, find the probability of drawing a black chip. There 3 chips in total and 1 is black, so the probability is:
P(black) =  \frac{1}{3}

Now, multiply the two previous answers:
P(even, black) =  \frac{1}{2}  * \frac{1}{3}  =  \frac{1}{6}

Finally the answer is:
P(even, black) =  \frac{1}{6}


Hope This Helped!
Cheers,
Izzy
Phoenix [80]2 years ago
4 0
C) 16 bc if you think about it like 25% chance you going to pull the same chip out without looking 

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The product \frac{b-5}{2b}\times\frac{b^2+3b}{b-5}=\frac{b+3}{2}

Step-by-step explanation:

Given expression \frac{b-5}{2b} and \frac{b^2+3b}{b-5}

We have to find the product of  \frac{b-5}{2b}\times\frac{b^2+3b}{b-5}

   

Consider the given expression  \frac{b-5}{2b}\times\frac{b^2+3b}{b-5}

Multiply fractions, we have,

\frac{a}{b}\cdot \frac{c}{d}=\frac{a\:\cdot \:c}{b\:\cdot \:d}

=\frac{\left(b-5\right)\left(b^2+3b\right)}{2b\left(b-5\right)}

Cancel common factor ( b - 5 )

we have, =\frac{b^2+3b}{2b}

Apply exponent rule,

\:a^{b+c}=a^ba^c

b^2=bb

=bb+3b=b(b+3)

=\frac{b\left(b+3\right)}{2b}

Cancel common factor b , we have,

=\frac{b+3}{2}

Thus, the product  \frac{b-5}{2b}\times\frac{b^2+3b}{b-5}=\frac{b+3}{2}

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2 years ago
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Step-by-step explanation:

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2 years ago
In Boston taxicabs charge an initial fare and an additional amount for every mile traveled. Tahira is having trouble figuring ou
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Answer:

The taxi charges $2.5 for every mile.

Step-by-step explanation:

We are given the following in the question:

Let x be the initial taxicab fare and y be the additional amount for every mile traveled.

Cost for a two mile ride = $7.00

Thus, we can write the equation:

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Cost of a nine mile ride = $24.50

Thus, we can write the equation,

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Solving the two equation by elimination method, we have,

x + 9y - (x + 2y) = 24.50 - 7\\7y = 17.5\\y = 2.5\\\Rightarrow x + 2(2.5) = 7\\x = 2

Thus, $2 is the initial fare and $2.5 is the cost for every mile traveled.

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2 years ago
Coach Wilson ordered T-shirts for the basketball team from two different T-shirt suppliers. One supplier charged $16 for each sh
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Part A:
# of shirts bought in total (T)times cost of each shirt (E) =X. X times .5 (same as 5%)= shipping charge (S) =
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Part B:
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# of shirts bought (A) times cost of each shirt (B) plus shipping charge(C) times 10%=T. A*B+C*.10=T

vendor 2:
# of shirts bought (A) times cost of each shirt (B) plus shipping charge (C) minus $20= T. A*B+C-20=T

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vendor 2:
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