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olganol [36]
2 years ago
9

Evaluate 4-0.25g+0.5h4−0.25g+0.5h4, minus, 0, point, 25, g, plus, 0, point, 5, h when g=10g=10g, equals, 10 and h=5h=5h, equals,

5.
Mathematics
2 answers:
Readme [11.4K]2 years ago
6 0

I believe the correct given equation is in the form of:

4 – 0.25 g + 0.5 h

Now we are to evaluate the equation with the given values:

g = 10 and h = 5

What this actually means is that to evaluate simply means to calculate for the value of the equation by plugging in the values of the variables. Therefore:

4 – 0.25 g + 0.5 h = 4 – 0.25 (10) + 0.5 (5)

4 – 0.25 g + 0.5 h = 4 – 2.5 + 2.5

4 – 0.25 g + 0.5 h = 4

 

Therefore the value of the equation is:

4

morpeh [17]2 years ago
6 0

Answer:

I believe the correct given equation is in the form of:

4 – 0.25 g + 0.5 h

Now we are to evaluate the equation with the given values:

g = 10 and h = 5

What this actually means is that to evaluate simply means to calculate for the value of the equation by plugging in the values of the variables. Therefore:

4 – 0.25 g + 0.5 h = 4 – 0.25 (10) + 0.5 (5)

4 – 0.25 g + 0.5 h = 4 – 2.5 + 2.5

4 – 0.25 g + 0.5 h = 4

 

Therefore the value of the equation is:

4

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Write the definition of a right angle in BICONDITIONAL form.*
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Step-by-step explanation:

5 0
2 years ago
The average lifetime of a certain new cell phone is 3.4 years. The manufacturer will replace any cell phone failing within three
melisa1 [442]

Answer:

68% of these phones last 3.87 years.

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

f(x) = \mu e^{-\mu x}

In which \mu = \frac{1}{m} is the decay parameter.

The probability that x is lower or equal to a is given by:

P(X \leq x) = \int\limits^a_0 {f(x)} \, dx

Which has the following solution:

P(X \leq x) = 1 - e^{-\mu x}

The probability of finding a value higher than x is:

P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}

The average lifetime of a certain new cell phone is 3.4 years.

This means that m = 3.4, \mu = \frac{1}{3.4} = 0.2941

So

P(X \leq x) = 1 - e^{-0.2941x}

68% of these phones last how long (in years)?

This is x for which:

P(X \leq x) = 0.68

P(X \leq x) = 1 - e^{-0.2941x}

Then

0.68 = 1 - e^{-0.2941x}

e{-0.2941x} = 0.32

\ln{e{-0.2941x}} = \ln{0.32}

-0.2941x = \ln{0.32}

x = -\frac{\ln{0.32}}{0.2941}

x = 3.87

68% of these phones last 3.87 years.

4 0
2 years ago
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