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olganol [36]
2 years ago
9

Evaluate 4-0.25g+0.5h4−0.25g+0.5h4, minus, 0, point, 25, g, plus, 0, point, 5, h when g=10g=10g, equals, 10 and h=5h=5h, equals,

5.
Mathematics
2 answers:
Readme [11.4K]2 years ago
6 0

I believe the correct given equation is in the form of:

4 – 0.25 g + 0.5 h

Now we are to evaluate the equation with the given values:

g = 10 and h = 5

What this actually means is that to evaluate simply means to calculate for the value of the equation by plugging in the values of the variables. Therefore:

4 – 0.25 g + 0.5 h = 4 – 0.25 (10) + 0.5 (5)

4 – 0.25 g + 0.5 h = 4 – 2.5 + 2.5

4 – 0.25 g + 0.5 h = 4

 

Therefore the value of the equation is:

4

morpeh [17]2 years ago
6 0

Answer:

I believe the correct given equation is in the form of:

4 – 0.25 g + 0.5 h

Now we are to evaluate the equation with the given values:

g = 10 and h = 5

What this actually means is that to evaluate simply means to calculate for the value of the equation by plugging in the values of the variables. Therefore:

4 – 0.25 g + 0.5 h = 4 – 0.25 (10) + 0.5 (5)

4 – 0.25 g + 0.5 h = 4 – 2.5 + 2.5

4 – 0.25 g + 0.5 h = 4

 

Therefore the value of the equation is:

4

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Vector bought 15.6 pounds of paintballs. All together, the balls cost $35.99.
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2 years ago
Three erasers and five pencils cost $7.55. 6 erasers and 12 pencils cost $17.40. How much does 1 eraser cost? How much does 1 pe
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Answer:

Step-by-step explanation:

erasers=e  

pencils=p

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6e+12p=17.40

divide by 2

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(2)-(1) gives

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from (1)

3e+5(1.15)=7.55

3e+5.75=7.55

3e=7.55-5.75

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7 0
2 years ago
It has been estimated that only about 30% of California residents have adequate earthquake supplies. Suppose we are interested i
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Answer:

Step-by-step explanation:

We are given that 30% of California residents have adequate earthquake supplies.

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C)The distribution of random variable is geometric distribution with parameter p=0.3

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P(X=x)=0.3(1-0.3)^{x-1} , x=1,2,3...

D)P(X=1) or P(X=2)=P(X=1)+P(X=2)

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E)

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F)

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p = 1-0.3 = 0.7

E(X)=\frac{1}{0.7}=1.42

G)E(X)=\frac{1}{q}=\frac{1}{0.3}=3.33

8 0
2 years ago
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