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olganol [36]
1 year ago
9

Evaluate 4-0.25g+0.5h4−0.25g+0.5h4, minus, 0, point, 25, g, plus, 0, point, 5, h when g=10g=10g, equals, 10 and h=5h=5h, equals,

5.
Mathematics
2 answers:
Readme [11.4K]1 year ago
6 0

I believe the correct given equation is in the form of:

4 – 0.25 g + 0.5 h

Now we are to evaluate the equation with the given values:

g = 10 and h = 5

What this actually means is that to evaluate simply means to calculate for the value of the equation by plugging in the values of the variables. Therefore:

4 – 0.25 g + 0.5 h = 4 – 0.25 (10) + 0.5 (5)

4 – 0.25 g + 0.5 h = 4 – 2.5 + 2.5

4 – 0.25 g + 0.5 h = 4

 

Therefore the value of the equation is:

4

morpeh [17]1 year ago
6 0

Answer:

I believe the correct given equation is in the form of:

4 – 0.25 g + 0.5 h

Now we are to evaluate the equation with the given values:

g = 10 and h = 5

What this actually means is that to evaluate simply means to calculate for the value of the equation by plugging in the values of the variables. Therefore:

4 – 0.25 g + 0.5 h = 4 – 0.25 (10) + 0.5 (5)

4 – 0.25 g + 0.5 h = 4 – 2.5 + 2.5

4 – 0.25 g + 0.5 h = 4

 

Therefore the value of the equation is:

4

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2 years ago
Nathan flew 3,547 miles from Canada to California during the first part of his trip. He flew 2,567 miles from California to Hawa
AURORKA [14]

Difference in the number of miles Nathan flew between the first and second parts of his trip is 980 miles

<em><u>Solution:</u></em>

Given that Nathan flew 3,547 miles from Canada to California during the first part of his trip

He flew 2,567 miles from California to Hawaii during the second part of his trip

Therefore,

first part of his trip = 3547 miles

second part of his trip = 2567 miles

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difference = first part of his trip - second part of his trip

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4 0
2 years ago
Automobile mechanics conduct diagnostic tests on 150 new cars of a particular make and model to determine the extent to which th
Aleks04 [339]

Answer:

99% Confidence interval: (0.185,0.375)                                                  

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 150

Number of cars that have faulty catalytic converters, x = 42

\hat{p} = \dfrac{x}{n} = \dfrac{42}{150} = 0.28

99% Confidence interval:

\hat{p}\pm z_{stat}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

z_{critical}\text{ at}~\alpha_{0.01} = \pm 2.58

Putting the values, we get:

0.28\pm 2.58(\sqrt{\frac{0.28(1-0.28)}{150}}) = 0.28\pm 0.095\\\\=(0.185,0.375)

The​ 99% confidence interval for the true proportion of new cars with faulty catalytic converters is​ (0.185,0.375)

8 0
2 years ago
Tonya has 39 packages. Each package weighs 58 pounds. Choose the best estimate of the total weight of the packages
kati45 [8]

Answer:

2400 lbs

Step-by-step explanation:

To find the best estimate, you have to round the numbers to the nearest ten.

39 -> 40

58 -> 60

40 x 60 = 2400

4 0
1 year ago
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