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TEA [102]
2 years ago
14

Evaluate the function rule for a given value y=12•3x for x=-2

Mathematics
1 answer:
Inessa [10]2 years ago
3 0
<span>y=12•3x for x=-2
</span><span>y=12•3(-2)
y = -72

hope it helps</span>
You might be interested in
The equation y=2x represents a set of data. Which statement is not true?
Sonja [21]

Answer:

Option D is correct

The initial value is 2

Step-by-step explanation:

The equation of line passes through the origin is represented by:

y = mx where m is the slope or unit rate .

Direct Proportionality says that:

if y \propto x then the equation of the form is y = kx where k is the constant of proportionality.

Given the equation: y = 2x

Then by definition:

m = 2

⇒ Slope on the line is 2.

⇒ the unit rate is 2.

Also, the constant of proportionality is 2.

Therefore, the statement which is not true for the equation y=2x represents a set of data is: The initial value is 2

7 0
2 years ago
Read 2 more answers
Suppose a company borrows 15,000 on 1/1/14 at 10% interest rate for a one year term. The company makes interest payments every q
goblinko [34]

Answer: 125

Step-by-step explanation:

Given that:

The principal = 15000

Rate = 10%

Years = 1 year = 12 month

Interest I = PRT/100

I = (15000 × 10 × 1)/100

I = 1500

The amount of interest expense that would they record in May will be

Interest = I/ 12 = 1500/12 = 125

5 0
2 years ago
A quality control engineer tests the quality of produced computers. suppose that 5% of computers have defects, and defects occur
11111nata11111 [884]
(a) 0.059582148 probability of exactly 3 defective out of 20

 (b) 0.98598125 probability that at least 5 need to be tested to find 2 defective.

  (a) For exactly 3 defective computers, we need to find the calculate the probability of 3 defective computers with 17 good computers, and then multiply by the number of ways we could arrange those computers. So

 0.05^3 * (1 - 0.05)^(20-3) * 20! / (3!(20-3)!)

 = 0.05^3 * 0.95^17 * 20! / (3!17!)

 = 0.05^3 * 0.95^17 * 20*19*18*17! / (3!17!)

 = 0.05^3 * 0.95^17 * 20*19*18 / (1*2*3)

 = 0.05^3 * 0.95^17 * 20*19*(2*3*3) / (2*3)

 = 0.05^3 * 0.95^17 * 20*19*3

 = 0.000125* 0.418120335 * 1140

 = 0.059582148

  (b) For this problem, let's recast the problem into "What's the probability of having only 0 or 1 defective computers out of 4?" After all, if at most 1 defective computers have been found, then a fifth computer would need to be tested in order to attempt to find another defective computer. So the probability of getting 0 defective computers out of 4 is (1-0.05)^4 = 0.95^4 = 0.81450625.

 The probability of getting exactly 1 defective computer out of 4 is 0.05*(1-0.05)^3*4!/(1!(4-1)!)

 = 0.05*0.95^3*24/(1!3!)

 = 0.05*0.857375*24/6

 = 0.171475

 
 So the probability of getting only 0 or 1 defective computers out of the 1st 4 is 0.81450625 + 0.171475 = 0.98598125 which is also the probability that at least 5 computers need to be tested.
3 0
2 years ago
The quotient of 24 and x equals 14 minus 2 times x (into an equation don’t solve)
Katen [24]

Answer:

24 / x = 14 - 2x

Step-by-step explanation:

Quotient means division (÷ or /)

Quotient of 24 and x = 24 ÷ x

24 ÷ x is equivalent to 24 / x

14 minus 2 times x = 14 - 2x

So, the equation is

24 / x = 14 - 2x

7 0
2 years ago
A large washer has an outer radius of 10mm and a hole with a diameter of 14mm. What is the area of the top surface of the washer
choli [55]
<h2>Answer:</h2>

The area of the top surface of the washer is:  160.14 square mm.

<h2>Step-by-step explanation:</h2>

The top of the surface is in the shape of a annulus  with a outer radius of 10 mm and a inner radius of 7 mm ( since the diameter of the hole is: 14 mm and we know that the radius is half of the diameter)

Now, we know that the area of the annulus region is given by:

Area=\pi (R^2-r^2)

where R is the outer radius and r is the inner radius.

Here we have:

R=10\ mm\\\\and\\\\r=7\ mm

Hence, we have:

Area\ of\ top\ surface=\pi (10^2-7^2)\\\\i.e.\\\\Area\ of\ top\ surface=\pi (100-49)\\\\i.e.\\\\Area\ of\ top\ surface=\pi\cdot 51\\\\i.e.\\\\Area\ of\ top\ surface=160.14\ mm^2

4 0
2 years ago
Read 2 more answers
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