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Gennadij [26K]
2 years ago
9

Factor the polynomial completely 11x^4y-22x^2y^2

Mathematics
1 answer:
Kazeer [188]2 years ago
8 0
The Greatest Common factor is 11x^2y  so the factors are
11x^2y(x^2 - 2y)
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The telephone company is planning to introduce two new types of executive communications systems that it hopes to sell to its la
cluponka [151]

Answer:

x = 31 hundred dolars   and      

y = 91/2 = 45.5 hundred dolars

Step-by-step explanation:

Given

R(x) = (40−8x+5y)*x + (50+9x−7y)*y

C(x) = (40−8x+5y)*10 + (50+9x−7y)*29

We can use the equation

P(x) = R(x) - C(x)

where

P(x) is the profit

R(x) is the revenue

and C(x) is the costs

In order to maximize the telephone company's profit, we apply

P'(x) = R(x)' - C(x)' = 0

⇒ R(x)' = ((40−8x+5y)*x + (50+9x−7y)*y)' = (40x-8x²+14xy+50y-7y²)'

⇒ C(x)' = ((40−8x+5y)*10 + (50+9x−7y)*29)' = (1850+181x-153y)'

⇒ P'(x) = -8x²-7y²-141x+203y+14xy-1850

The first-order partial derivatives of these functions are

Px(x,y) = -16x-141+14y

Py(x,y) = -14y+203+14x

Setting these equal to zero and solving we obtain:

-16x+14y-141 = 0

14x-14y+203=0

we get the solution

x = 31     and       y = 91/2 = 45.5

Finally, the company should produce  3100  units of the first system, and  4550 units of the second system.

8 0
2 years ago
Lamar shares 6 pencils equally with himself and 5 friends. Write an equation and solve to show the number of pencils each friend
kkurt [141]
6 pencils÷ lamer+5 other friends=1.1 pencil for each person
3 0
2 years ago
Read 2 more answers
Kyle asks his friend Jane to guess his age and his grandmother’s age. Kyle says his grandmother is not more than 80 years old. H
melamori03 [73]
#1 is incorrect. The first equation says that his grandmother is not more than 80 years old. If you confine yourself to whole numbers, then she could be 80 but not more. That inequality should be written as g < 81 or if you are a purist, g≤ 80. 

The second equation is correct. At the very most her age is equal to 3k - 3 so at most it would be written as g = 3k - 3.

Since it is not that much, you would write it as g ≤ 3k - 3
6 0
2 years ago
Read 2 more answers
A mechanical dart thrower throws darts independently each time, with probability 10% of hitting the bullseye in each attempt. Th
Arturiano [62]

Answer:

The probability of hitting the bullseye at least once in 6 attempts is 0.469.

Step-by-step explanation:

It is given that a mechanical dart thrower throws darts independently each time, with probability 10% of hitting the bullseye in each attempt.

The probability of hitting bullseye in each attempt, p = 0.10

The probability of not hitting bullseye in each attempt, q = 1-p = 1-0.10 = 0.90

Let x be the event of  hitting the bullseye.

We need to find the probability of hitting the bullseye at least once in 6 attempts.

P(x\geq 1)=1-P(x=0)       .... (1)

According to binomial expression

P(x=r)=^nC_rp^rq^{n-r}

where, n is total attempts, r is number of outcomes, p is probability of success and q is probability of failure.

The probability that the dart thrower not hits the bullseye in 6 attempts is

P(x=0)=^6C_0(0.10)^0(0.90)^{6-0}

P(x=0)=0.531441

Substitute the value of P(x=0) in (1).

P(x\geq 1)=1-0.531441

P(x\geq 1)=0.468559

P(x\geq 1)\approx 0.469

Therefore the probability of hitting the bullseye at least once in 6 attempts is 0.469.

3 0
2 years ago
Trapezoid EFGH has coordinates E(−3, 4) , F(1, 4), G(3, 1) , and H(−5, 1) . Trapezoid E'F'G'H' has coordinates E′(−12, 16) , F′(
julia-pushkina [17]
I believe that the answer would be C
8 0
2 years ago
Read 2 more answers
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