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MrRissso [65]
2 years ago
10

An ice cream store has two new flavors: Fantasy and Ecstasy. Each barrel of Fantasy requires 4

Mathematics
1 answer:
Y_Kistochka [10]2 years ago
8 0

Answer:

  • Fantasy: 3 barrels
  • Ecstasy: 1 barrel

Step-by-step explanation:

<u>Given</u>

  Fantasy uses 4 lb of nuts, 3 lb of chocolate, for a profit of $50

  Ecstasy uses 4 lb of nuts, 1 lb of chocolate, for a profit of $40

  In stock are 16 lb of nuts, 10 lb of chocolate

<u>Find</u>

 amount of each to maximize profit

<u>Solution</u>

Let x and y represent barrels of Fantasy and Ecstasy, respectively. Then the limitations on production are ...

  4x +4y ≤ 16 . . . lb of nuts

  3x +y ≤ 10 . . . . lb of chocolate

We want to maximize

  50x +40y

The graph shows the feasible region. Its vertices are ...

  (0, 4), (3, 1), (3.33, 0)

Profit is maximized at $190 when production is 3 barrels of Fantasy and 1 barrel of Ecstasy.

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One of the sides of a parallelogram is 4.2 cm and the altitude to that side is 3.6 cm. Find the perimeter of the parallelogram i
dexar [7]

Area of parallelogram = base * height
base 1 = 4.2 cm
height 1 = 3.6 cm
∴ Area = 4.2 * 3.6 = 15.12

let the other base 2 = x
∴ the altitude of this base = height 2 = 2.4
∴Area = 2.4 x = 15.12
Solve for x
                 ∴ x = 6.3 cm

∴ The perimeter of parallelogram = 2( base 1 + base 2)
                                                      = 2 ( 4.2 + 6.3 ) = 21 cm



7 0
2 years ago
Kim solved the equation below by graphing a system of equations. log2(3x-1)= log4(x+8) What is the approximate solution to the e
kifflom [539]

Answer:

(1.35, 1.6)

Step-by-step explanation:

A screenshot of the graph is attached.

Once we graph the equations y=\log_2(3x-1) and y=\log_4(x+8), the solution to this system will be their intersection point.

Tracing the graph on the calculator, we see that the point of intersection is at about (1.35, 1.6).

6 0
2 years ago
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When Ryan is serving at a restaurant, there is a 0.75 probability that each party will order drinks with their meal. During one
Triss [41]

Answer:

0.82 = 82% probability that at least one party will not order drinks

Step-by-step explanation:

For each party, there are only two possible outcomes. Either they will order drinks with their meal, or they will not. The probability of a party ordering drinks with their meal is independent of other parties. So the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

When Ryan is serving at a restaurant, there is a 0.75 probability that each party will order drinks with their meal.

This means that p = 0.75

During one hour, Ryan served 6 parties. Assuming that each party is equally likely to order drinks, what is the probability that at least one party will not order drinks?

6 parties, so n = 6.

Either all parties will order drinks, or at least one will not. The sum of the probabilities of these events is decimal 1. So

P(X = 6) + P(X < 6) = 1

We want P(X < 6). So

P(X < 6) = 1 - P(X = 6)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 6) = C_{6,6}.(0.75)^{6}.(0.25)^{0} = 0.18

P(X < 6) = 1 - P(X = 6) = 1 - 0.18 = 0.82

0.82 = 82% probability that at least one party will not order drinks

5 0
2 years ago
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Find the area of the triangle with the given measurements. Round the solution to the nearest hundredth if necessary. B = 105°, a
Akimi4 [234]

Answer:

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Step-by-step explanation:

It is given that AB=19cm, BC=12cm and ∠B=105°

Now, Area of the triangle ABC=\frac{1}{2}acsinB

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=6{\times}19{\times}(0.965)

=110.10cm^{2}

Thus, the area of triangle is 110.10cm^{2}

4 0
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attashe74 [19]

7:8 it could also be written as 7 to 8 or 7/8

Since we need to find out SIXTH to FIFTH grades we have to put the sixth graders first. Hope this helps and have a great day!

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