Answer:
He earned $114 in interest.
The final amount in the account is $874
Step-by-step explanation:
Initial balance (b): $760
Interest rate (i): 0.05
Period (n): 3 months
Simple interest applications yield the same amount in interest every period. Therefore, the total simple interest earned can be defined by:
The final amount (A) in the account is the initial balance plus the interest earned in 3 months.
He earned $114 in interest and the final amount in the account is $874
Answer:
Confidence limit = [52.8%, 75.2%]
Step-by-step explanation:
± 
where the value will be taken from the z-table for 95% confidence interval
1-0.95= 0.05/2= 0.025
0.95+0.025= 0.0975
From the z-table the value of corresponding to 0.0975 is 1.96
± 
± 
± 
% ± 
%
so the confidence interval is
%
%
![[52.8, 75.2]](https://tex.z-dn.net/?f=%5B52.8%2C%2075.2%5D)
*Given
3(x+y)=y
y is not equal to zero
*Solution
1. The given equation is 3(x+y) = y and we are tasked to find the ratio between x and y. Distributing 3 to the terms in the parenthesis,
3(x+y) = y
3x + 3y = y
Transposing 3y to the right side OR subtracting 3y from both the left-hand side and the right-hand side of the equation would give
3x = -2y
Dividing both sides of the equation by 3,
x = (-2/3)y
Dividing both sides of the equation by y,
x/y = -2/3
Therefore, the ratio x/y has a value of -2/3 provided that y is not equal to zero.
Answer:
2/105
Step-by-step explanation:
"r" is the greatest common divisor (GCD) of the two fractions. It can be found using Euclid's algorithm in the usual way.
(8/15) - (18/35) = 56/105 - 54/105 = 2/105 . . . . . this is (8/15) mod (18/35)
We can see that the next step, division of 54/105 by 2/105, will produce a remainder of 0, so the GCD is 2/105.
The greatest rational number r is 2/105.
_____
<em>Check</em>
The ratios are (8/15)/(2/105) = 28; (18/35)/(2/105) = 27. These whole numbers are relatively prime, so there is no larger r than the one we found.
Answer: la altura es 13.1 m
Step-by-step explanation:
El movimiento descripto es de tipo rectilineo uniformemente variado, más precisamente tiro vertical.
Para calcular la posición al cabo de 1 seg utilizaremos la ecuacionecuación del movimiento descrita como:
y = v0.t - 1/2 g t^2
Donde y es la altura para cualquier momento
v0 es la velocidad inicial 18 m/s
g la aceleración de la gravedad 9.81 m/s2
y t el tiempo medido en segundos
Entonces para calcular la altura después de un segundo:
y = 18 m/s x 1 seg - 1/2 9.81 m/s2 (1 seg)^2 = 18 m - 4.9 m = 13.1 m
