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FrozenT [24]
2 years ago
10

A candy manufacturer makes two types of special candy, say A and B. Candy A consists of equal parts of dark chocolate and carame

l and Candy B consists of two parts of dark chocolate and one part of walnut. The company has in stock 430 kilograms of caramel, 360 kilograms of dark chocolate, and 210 kilograms of walnuts. The company sells Candy A for P285 and Candy B for P260 per kilograms. How much of each candy should the manufacturer produce to maximize profit?
Mathematics
1 answer:
Sphinxa [80]2 years ago
6 0
If we let x as candy A
y as candy B
a as dark chocolate in candy a
b as dark chocolate in candy b
c as caramel
d as walnut
P as profit
we have the equations:
a + c = x
2b + d = y
a + 2b ≤ 360
c ≤ 430
d ≤ 210
P = 285x + 260y

This is an optimization problem which involves linear programming. It can be solved by graphical method or by algebraic solution.
P = 285(a + c) + 260(2b +d)
If we assume a = b
Then a = 120, 2b = 240
P = 285(120 + 120) + 260(240 + 120)
P = 162000
candy A should be = 240
candy B should be = 360
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Jen and Ariel are reading a 400 page novel for their literature class. Jen decides to read 100 pages the first day and 50 pages
Furkat [3]

Answer:

Option B is the correct answer.

Step-by-step explanation:

Jen decides to read 100 pages the first day and 50 pages each day thereafter.

Number of pages read by Jen per day = 50

Number of pages read by Jen on first day = 100

Ariel's progress on reading the book is represented by the linear function y = 40x + 80, where y is the total number of pages read after x days.

Number of pages read by Ariel per day = 40

Number of pages read by Ariel on first day = 40 + 80 = 120

Option A:

Jen reads 20 pages per day more than Ariel

Wrong

Option B:

Ariel reads 10 pages per day less than Jen.

Correct

Option C:

Ariel read 20 pages less the first day than Jen read.

Wrong

Option D:

The reading rate each day for Jen and Ariel is the same.

Wrong

Option B is the correct answer.

6 0
2 years ago
Read 2 more answers
3. Tom, Sam and Matt are counting drum beats.
just olya [345]

Answer:

<em>When 60 beats are heard, Tom hits 15 snare drums, Sam hits 6 kettle drums, and Matt hits 5 bass drums.</em>

Step-by-step explanation:

The Least Common Multiple ( LCM )

The LCM of two integers a,b is the smallest positive integer that is evenly divisible by both a and b.

For example:

LCM(20,8)=40

LCM(35,18)=630

Since Tom, Sam, and Matt are counting drum beats at their own frequency, we must find the least common multiple of all their beats frequency.

Find the LCM of 4,10,12. Follow this procedure:

List prime factorization of all the numbers:

4 = 2*2

10 = 2*5

12 = 2*2*3

Multiply all the factors the greatest times they occur:

LCM=2*2*3*5=60

Thus, when 60 beats are heard, Tom hits 15 snare drums, Sam hits 6 kettle drums, and Matt hits 5 bass drums.

6 0
2 years ago
Two bicyclists are 7/8 of the way through a mile long tunnel when a train approaches the closer end at 40 mph. The riders take o
Anastaziya [24]

Answer:

the cyclists rode at 35 mph

Step-by-step explanation:

Assuming that the cyclists stopped, and accelerated instantaneously at the same speed than before but in opposite direction , then

distance= speed*time

since the cyclists and the train reaches the end of the tunnel at the same time and denoting L as the length of the tunnel :

time = distance covered by cyclists / speed of cyclists = distance covered by train / speed of the train

thus denoting v as the speed of the cyclists :

7/8*L / v = L / 40 mph

v = 7/8 * 40 mph = 35 mph

v= 35 mph

thus the cyclists rode at 35 mph

6 0
2 years ago
Jake came in second place in the long jump at his track meet. The winner jumped a distance of 29.18 feet and the person in third
IRISSAK [1]
Answer: 29
Any number between 28.83 and 29.18 would work
8 0
2 years ago
A car with 15 gallons of gasoline drives 420 miles until the tank is empty. Write a linear equation that describes the amount of
DedPeter [7]

Answer:

g = 15 - m/28

Step-by-step explanation:

let g = gasoline

let m = miles

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since you can drive 420 miles with 15 gallons of gas, you can drive 28 miles with one gallon (= 420/15 = 28)

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you drive 100 miles, then you will have:

g = 15 - 100/28 = 15 - 3.57 = 11.43 gallons of gas left

you drive 240 miles:

g = 15 - 240/28 = 6.43 gallons

4 0
2 years ago
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