Answer:
18 students are likely to be wearing red
Step-by-step explanation:
From the question, we know a student either wears red , or blue, with the probability of a student wearing red is 3 times more probable than wearing white.
So, let’s say out of the 24 students, x of them are wearing white. What this practically mean is that 3 * x = 3x of the students would be expected to be wearing red.
Now, adding the number of people wearing red and white together in terms of x, we have x + 3x = 4x
We equate this to 24; 4x = 24 and x = 24/4; x = 6
The number wearing red probably is 3 * x = 3 * 6 = 18 people
Answer:
40.1%
Step-by-step explanation:
I am assuming that 192 is in 100%.
100% = 192
I then represent the value that we are looking for with 
.
x% = 77
By dividing both equations (100% = 192 and x% = 77) and remembering that both left hand sides of BOTH equations have the percentage unit (%).
Now, of course, we take the reciprocal, or inverse, of both sides:
x = 40.1%
Thus making the answer: 40.1% of 192 is 77.
<span>My answer was D. 13.9 yd.
It depends on which leg is 12 yds
If it's the short one, hyp = 24
If the other one, hyp = 13.9
hope this works
</span>
The solution for this problem would be:
Given that there is 99.999%.
Let denote n as the network servers and p as the reliability of each server.
So the probability that the network uptime = 1 - (1 - p)^n
Therefore, (1-p) ^n = 0.00001
a. x= log(1-.99999)÷log(1-.97)= 3.2833 is the answer
1-(1-.97)^3= 0.99999 + 0.0001 = 1
b. x = log(1-.99999)÷log(1-.88) = 5.43 is the answer
1-(1-.88)^3= 0.99 + 0.0001 = approx 1
