c(x)=9x+89
I know that you don't have the answer listed, but it is the correct answer.
Answer:
We need a non-included side of one triangle
Step-by-step explanation:
By means of the AAS postulate.
The Angle-Angle-Side postulate (AAS) tells us that if two angles and a non-included side of one triangle are congruent to two angles and the corresponding non-included side of another triangle, then the two triangles are congruent.
The area of polygon D is given by:
Ad = k ^ 2 * Ac
Where,
k: scale factor
Ac: area of polygon C
Substituting the values we have:
Ad = (1/2) ^ 2 * (40)
Ad = (1/4) * (40)
Ad = 10 square units
Answer:
the area of Polygon D is:
Ad = 10 square units
Answer:
(x) = x - 5
Step-by-step explanation:
Let y = f(x) and make x the subject
y = x + 5 ( subtract 5 from both sides )
y - 5 = x
Change y back into terms of x, thus
(x) = x - 5