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2 years ago

Vector bought 15.6 pounds of paintballs. all together, the balls cost 35.99. About how much dis the psinballs cost per pond?

2 answers:

8 0

Since 15.6lbs cost $35.99, we can find out how much 1 pound costs by setting up a proportion.

15.6 : 35.99
1 : x

x = 35.99*1 / 15.6
x = 2.30

1 pound costs $2.30.

nevsk [136]2 years ago

6 0

Paintballs are $2.30 per pound.

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2 years ago

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5. A metal ornament is being designed such that its perimeter is created by four identical three-quarter circles

Mnenie [13.5K]

Answer:

(a) 12π in

(b) 53.5 in

Step-by-step explanation:

In the figure attached, the ornament is shown

(a) four three-quarter circles is equivalent to 4*3/4 = 3 circles. The perimeter of a circle is the total length of the circular portions.

Perimeter of each circle: 2*π*r

The radius is 2 in long, then for 3 circles:

Perimeter = 3*2*π*2 = 12π in

(b) Perimeter of square: 4*side length

The side length of the square is 4 in, then:

Total length of wire needed = 4*4 + 12π = 53.5 in

total weight of the ornament = 1.8 grams/in * 53.5 in = 96 grams

4 0

2 years ago

Math 9:The floor of conference hall can be covered completely with tiles. Its length is 36 ft longer than its width. The area of

valentina_108 [34]

What is the question?
I'm assuming it is to find the length and width.
+_= plus or minus
(X+36)
____________
| |
(X) | |
|____________|

X^2+36X-2040<0
X<-36+_(36^2-4*-2040)^(1/2)
-----------------------------------
2
X<-18+_2((591)^(1/2))
This is probably not what you wanted, sorry

8 0

2 years ago

Sales tax in one state is 4%. What is the amount of tax on a $56.70 purchase?

NeTakaya

1) Convert 4% to decimal = .04

2) Multiply the purchase by that decimal

.04(56.70) = $2.27

5 0

2 years ago

"Immediately after a ban on using hand-held cell phones while driving was implemented, compliance with the law was measured. A r

sergiy2304 [10]

Answer:

(a) Null Hypothesis, $H_0$ : $p_1-p_2=0$ or $p_1= p_2$

Alternate Hypothesis, $H_A$ : $p_1-p_2\neq 0$ or $p_1\neq p_2$

(b) We conclude that there is a statistical difference in these two proportions measured initially and then one year later.

Step-by-step explanation:

We are given that a random sample of 1,250 drivers found that 98.9% were in compliance. A year after the implementation, compliance was again measured to see if compliance was the same (or not) as previously measured.

A different random sample of 1,100 drivers found 96.9% compliance."

Let $p_1$ = proportion of drivers that were in compliance initially

$p_2$ = proportion of drivers that were in compliance one year later

(a) Null Hypothesis, $H_0$ : $p_1-p_2=0$ or $p_1= p_2$ {means that there is not any statistical difference in these two proportions measured initially and then one year later}

Alternate Hypothesis, $H_A$ : $p_1-p_2\neq 0$ or $p_1\neq p_2$ {means that there is a statistical difference in these two proportions measured initially and then one year later}

The test statistics that will be used here is Two-sample z proportion statistics;

T.S. = $\frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{ \frac{\hat p_1(1-\hat p_1)}{n_1} + \frac{\hat p_2(1-\hat p_2)}{n_2}} }$ ~ N(0,1)

where, $\hat p_1$ = sample proportion of drivers in compliance initially = 98.9%

$\hat p_2$ = sample proportion of drivers in compliance one year later = 96.9%

$n_1$ = sample of drivers initially = 1,250

$n_2$ = sample of drivers one year later = 1,100

(b) So, the test statistics = $\frac{(0.989-0.969)-(0)}{\sqrt{ \frac{0.989(1-0.989)}{1,250} + \frac{0.969(1-0.969)}{1,100}} }$

= 3.33

Now, P-value of the test statistics is given by;

P-value = P(Z > 3.33) = 1 - P(Z $\leq$ 3.33)

= 1 - 0.99957 = 0.00043

Since in the question we are not given with the level of significance so we assume it to be 5%. Now at 5% significance level, the z table gives critical values between -1.96 and 1.96 for two-tailed test.

Since our test statistics does not lies within the range of critical values of z, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that there is a statistical difference in these two proportions measured initially and then one year later.

7 0

2 years ago