Given:
On the first day, she drove 650 miles in 10 hours.
On the second day, she got a later start and drove 540 miles in 8 hours.
To find:
Difference between average speed of second day and first day.
Solution:
We know that,
On the first day, she drove 650 miles in 10 hours. So, the average speed is
So, the average speed on first day is 65 miles per hour.
On the second day, she got a later start and drove 540 miles in 8 hours.
So, the average speed on second day is 67.5 miles per hour.
Difference between average speed is
Therefore, the average speed on the second day is 2.5 miles per hour is faster than first day.
Answer:
B. AD = sqrt(CD * BD)
Step-by-step explanation:
By the right triangle altitude theorem,
CD/AD = AD/BD
AD^2 = CD * BD
AD = sqrt(CD * BD)
Answer: B. AD = sqrt(CD * BD)
C. eight or fewer
99% means 99/100
. with 9 alarms there is no way you can trigger 8 alarms with that 99% rate
Answer:
10,000,000
Step-by-step explanation:
you round up, so that makes it 10,000,000
Answer:
40 * x - 600 = 0
Step-by-step explanation:
The first thing is to identify the variable (x) of the equation and they will be the number of days that Leilah will take to read her flashcards. Now if you need to study 600 out of 2400, it is because you have read 1800. Therefore we have to:
2400 - 1800 = 40 * x
rearranging
40 * x - 600 = 0
The above would be the equation of the situation
