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jolli1 [7]
2 years ago
5

Which expression is equivalent to 3 256x^10y^7

Mathematics
1 answer:
Leviafan [203]2 years ago
3 0
3 \sqrt{256 \ \times x^{10} y^{7} }

------------------------------------
square root of 256 is 16 :
------------------------------------
= 48 \sqrt{x^{10} y^{7}}

------------------------------------
√10¹⁰ = 10⁵ :
------------------------------------
= 48x^5 \sqrt{ y^{7}}

------------------------------------
√y⁶ = y³ :
------------------------------------
= 48x^5y^3 \sqrt{ y}}



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jolli1 [7]

Answer:

That the number 1 has this property.

Step-by-step explanation:

For base step we have to prove that number 1 has the property.

so therefore the smallest number of S is 1.

So that the number 1 has this property.

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Writing two column proofs<br> Given: BC bisects. ABD M ABD =52° prove: mABC=26°
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Given

BC bisects ABD

∠ ABD =52°

prove: m ∠ABC=26°

To proof

As given in the question

BC bisects ∠ABD

This means BC divided ∠ABD into the two equal parts.

Therefore

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put this in the above value

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\angle ABC =\frac{1}{2}52^{\circ}

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Hence proved

 


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Step-by-step explanation:

Just did it

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Suppose the weights of fish caught from pier 1 and pier 2 are normally distributed with equal population standard deviations. Th
madreJ [45]

Answer:

<em>H₀</em>: <em>μ</em>₁ = <em>μ</em>₂ vs, <em>Hₐ</em>: <em>μ</em>₁ > <em>μ</em>₂.

Step-by-step explanation:

A two-sample <em>z</em>-test can be performed to determine whether the claim made by the owner of pier 1 is correct or not.

It is provided that the weights of fish caught from pier 1 and pier 2 are normally distributed with equal population standard deviations.

The hypothesis to test whether the average weights of the fish in pier 1 is more than pier 2 is as follows:

<em>H₀</em>: The weights of fish in pier 1 is same as the weights of fish in pier 2, i.e. <em>μ</em>₁ = <em>μ</em>₂.

<em>Hₐ</em>: The weights of fish in pier 1 is greater than the weights of fish in pier 2, i.e. <em>μ</em>₁ > <em>μ</em>₂.

The significance level of the test is:

<em>α</em> = 0.05.

The test is defined as:

z=\frac{(\bar x_{1}-\bar x_{2})-(\mu_{1}-\mu_{2})}{\sqrt{\frac{\sigma_{1}^{2}}{n_{1}}+\frac{\sigma_{2}^{2}}{n_{2}}}}

The decision rule for the test is:

If the <em>p</em>-value of the test is less than the significance level of 0.05 then the null hypothesis will be rejected and vice-versa.

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