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AysviL [449]
2 years ago
11

Tickets for a basketball game cost $20 for upper-level seats and $30 for lower-level seats. Tickets at the same venue

Mathematics
2 answers:
Savatey [412]2 years ago
7 0

Answer:

A and c

Step-by-step explanation:

nika2105 [10]2 years ago
5 0

Answer:

200 and 100

Step-by-step explanation:

Just did it:)

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The ratios in an equivalent ratio table are 3:12, 4:16, and 5:20. If the first number in theratio is 10, what is the Second numb
Zanzabum

Answer:

10:40

Step-by-step explanation:

As the left number increases by 1, the right number increases by 4. So as you can see, the left numbers go 3-4-5 while the right numbers go 12-16-20. So the answer is 10:40 because 10x4=40.

6 0
2 years ago
Read 2 more answers
A car bought $52,000 and sold for $42,000. The percentage lost is?
mamaluj [8]

Calculate the difference between purchase and sales costs:

$52,000 - $42,000 = $10,000

Calculate what fraction of $52,000 is $10,000:

\dfrac{\$10,000}{\$52,000}=\dfrac{10}{52}=\dfrac{5}{26}

Transform it to the percent:

\dfrac{5}{26}=\dfrac{5}{26}\cdot100\%=\dfrac{500}{26}\%\approx19\%

<h3>Answer: A. 19%</h3>
8 0
2 years ago
A line contains the points (82, −96) and (87, −86).
Alik [6]

Answer:

<h2>The answer is 2</h2>

Step-by-step explanation:

The slope of a line given two points can be found by using the formula

m =  \frac{ y_2 - y _ 1}{x_ 2 - x_ 1} \\

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

(82, −96) and (87, −86)

We have

m =  \frac{ - 86 -  - 96}{87 - 82}  =  \frac{ - 86 + 96}{5}  =  \frac{10}{5}  = 2 \\

We have the final answer as

<h3>2 </h3>

Hope this helps you

8 0
2 years ago
Describe the first step when factoring any polynomial. Why is this the first step? Explain.
seropon [69]
Step 1: If there is a common factor, factor out the GCF. Step 2<span>: Identify the number of terms: (i) If polynomial has two terms, convert polynomial into difference of two squares or sum of two cubes or difference of two cubes.</span>
3 0
2 years ago
Read 2 more answers
Evaluate the line integral by the two following methods. xy dx + x2y3 dy C is counterclockwise around the triangle with vertices
nadezda [96]

Answer:

a)

\frac{2}{3}

b)

\frac{2}{3}

Step-by-step explanation:

a) The first part requires that we use line integral to evaluate directly.

The line integral is

\int_C xydx +  {x}^{2}  {y}^{3} dy

where C is counterclockwise around the triangle with vertices (0, 0), (1, 0), and (1, 2)

The boundary of integration is shown in the attachment.

Our first line integral is

L_1 = \int_ {(0,0)}^{(1,0)} xydx +  {x}^{2}  {y}^{3} dy

The equation of this line is y=0, x varies from 0 to 1.

When we substitute y=0 every becomes zero.

\therefore \: L_1 =0

Our second line integral is

L_2 = \int_ {(1,0)}^{(1,2)} xydx +  {x}^{2}  {y}^{3} dy

The equation of this line is:

x = 0 \implies \: dx = 0

y varies from 1 to 2.

We substitute the boundary and the values to get:

L_2 = \int_ {1}^{2}1 \cdot y(0) +  {1}^{2}   \cdot \: {y}^{3} dy

L_2 = \int_ {1}^2 {y}^{3} dy =  \frac{8}{3}

The 3rd line integral is:

L_3 = \int_ {(1,2)}^{(0,0)} xydx +  {x}^{2}  {y}^{3} dy

The equation of this line is

y = 2x \implies \: dy = 2dx

x varies from 0 to 1.

We substitute to get:

L_3 = \int_ {1}^{0} x \cdot \: 2xdx +  {x}^{2}  {(2x)}^{3}(2 dx)

L_3 = \int_ {1}^{0} 8 {x}^{5}  + 2 {x}^{2} dx  =  - 2

The value of the line integral is

L = L_1 + L_2 + L_3

L = 0 +  \frac{8}{3}  +  - 2 =  \frac{2}{3}

b) The second part requires the use of Green's Theorem to evaluate:

\int_C xydx +  {x}^{2}  {y}^{3} dy

Since C is a closed curve with counterclockwise orientation, we can apply the Green's Theorem.

This is given by:

\int_C \: Pdx +Q  \: dy =  \int \int_ R \: Q_y -  P_x \: dA

\int_C \: xydx + {x}^{2} {y}^{3}   \: dy =  \int \int_ R \: 3 {x}^{2}  {y}^{2}  -  y \: dA

We choose our region of integration parallel to the y-axis.

\int_C \: xydx + {x}^{2} {y}^{3}   \: dy =  \int_ 0^{1} \int_ 0^{2x}  \: 3 {x}^{2}  {y}^{2}  -  y \: dydx

\int_C \: xydx + {x}^{2} {y}^{3}   \: dy =  \int_ 0^{1} \:  {x}^{2}  {y}^{3}  -   \frac{1}{2}  {y}^{2} |_ 0^{2x}  dx

\int_C \: xydx + {x}^{2} {y}^{3}   \: dy =  \int_ 0^{1} \:  8{x}^{5} -  2 {x}^{2}   dx =  \frac{2}{3}

8 0
2 years ago
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