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ololo11 [35]
2 years ago
11

When planning a party you want to know whom to invite. Among the people you would like to invite are three touchy friends.You kn

ow that if Jasmine attends, she will become unhappy if Samir is there, Samir will attend only if Kanti will be there, and Kanti will not attend unless Jasmine also does.Which combinations of these three friends can you invite so as not to make someone unhappy?
Mathematics
1 answer:
harkovskaia [24]2 years ago
5 0

Answer:

Jasmine only.

Jasmine and Kanti only.

No one.

Step-by-step explanation:

There is no possible way to invite all three friends.

Since both Samir and Kanti will not attend if someone else is not invited, Jasmine is the only friend that can be invited on her own:

One person: Jasmine.

When inviting two people, if Jasmine is invited, Samir can't be invited and Kanti will only attend if Jasmine also does. Therefore, Jasmine and Kanti can go together and there is no way Kanti can be invited.

Two people: Jasmine and Kanti.

Furthermore, if nobody is invited, no one will be unhappy.

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The triangles shown below must be congruent. True or false
Alex777 [14]
The correct answer to your question is false. this is because congruent triangles must have the same 3 angles and the same 3 sides, and while these triangles have the same angles, they dont have the same sides.
let me know if you have any other questions
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4 0
2 years ago
Read 2 more answers
Consider the function represented by the equation y-6x-9=0. Which answer shows the equation written in function notation with x
Marta_Voda [28]

Answer:

A. f(x) = 6x + 9

Step-by-step explanation:

The given equation is:

y - 6x - 9 = 0

We have to write this equation in function notation with x as the independent variable. This means that y will be replaced by f(x) and all other terms will be carried to the other side of the equation to get the desired function notation.

y - 6x - 9 = 0

y = 6x + 9

f(x) = 6x + 9

Therefore, option A gives the correct answer.

5 0
2 years ago
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EVELYN HAD 9 DOLLS, BUT SHE LOST 1/3RD OF THEM AT DAYCARE. HOW MANY TOTAL DOLLS WOULD EVELYN HAVE HAD IF SHE HAD NOT LOST THEM?
Elanso [62]

Answer:

Total Dolls would Evelyn have had if she had not lost them = 9 Dolls

Step-by-step explanation:

As given,

Total dolls Evelyn had = 9

Total dolls lost = \frac{1}{3}× 9 = 3

So, Now

Evelyn had total dools after lost = 9 - 3 = 6

If she had not lost te dolls , then she had 3 dolls more

∴ we get

If she had not lost any dolls , Evelyn had total dolls = 6 + 3 = 9

So, The answer would be :

Total Dolls would Evelyn have had if she had not lost them = 9 Dolls

3 0
1 year ago
A rectangular prism has a length of 412 millimeters, a width of 412 millimeters, and a height of 6 millimeters. Sally has a stor
Dominik [7]
Multiply the length*width*height to get the volume of the prism then, take out the difference between the volumes
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Then just subtract
0 0
2 years ago
A circle with radius of \greenD{6\,\text{cm}}6cmstart color #1fab54, 6, start text, c, m, end text, end color #1fab54 sits insid
Diano4ka-milaya [45]

Answer: 141 cm^{2}

Step-by-step explanation:

We have two circles:

Cirlce 1, with a radius r=6 cm and area A_{1}:

A_{1}=\pi r^{2}

And Cicle 2, with a radius R=9 cm and area A_{2}:

A_{1}=\pi R^{2}

Since Circle 1 is inside Circle 2 and assuming the area of the shaded region is the shown in the attached image, its area is:

A=A_{2}-A_{1}=\pi R^{2}-\pi r^{2}

A=\pi (R^{2}- r^{2})

A=\pi ((9cm)^{2}- (6cm)^{2})

Finally:

A=141.37 cm^{2} \approx 141 cm^{2}

3 0
2 years ago
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