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const2013 [10]
2 years ago
14

Circle C is shown. Secants U W and Y W intersect at point W outside of the circle. Secant U W intersect the circle at point V an

d secant Y W intersects the circle at point X.
In the diagram of circle C, m∠VWX is 43°. What is mArc V X?

39°
41°
78°
82°
Mathematics
1 answer:
Nookie1986 [14]2 years ago
4 0
78 degrees mArc V X in the diagram
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What is equal to x in x - 8pi = pi?
pochemuha

Add 8π to both sides of the equation to get:

x - 8\pi + 8\pi = \pi + 8 \pi

\boxed{x = 9 \pi}


We have found that x = 9π. Remember that in solving problems like these with pi that it can often be helpful to treat pi as a variable.

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Check all statements that are equivalent to If the sky is not clear, then you don't see the stars ? a. Clear sky is necessary an
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Answer: The answer is G

Step-by-step explanation:

If you don't see the stars, then the sky is not clear. This statement is equivalent to saying "If the sky is not clear, then you don't see the stars", because if you rearrange both statements you will find out that they are equivalent to each other.

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2 years ago
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According to a study in a medical journal, 202 of a sample of 5,990 middle-aged men had developed diabetes. It also found that m
tekilochka [14]

Answer:

0.0588 = 5.88% probability that a middle-aged man with diabetes is very active

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Has diabetes.

Event B: Is very active.

Probability of having diabetes:

To find this probability, we take in consideration that:

It also found that men who were very active (burning about 3,500 calories daily) were a fourth as likely to develop diabetes compared with men who were sedentary. Assume that one-fifth of all middle-aged men are very active, and the rest are classified as sedentary.

So the probability of developing diabetes is:

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P(A) = 0.8x + 0.25*0.2x = 0.85x

Probability of developing diabetes while being very active:

0.25x of 0.2. So

P(A \cap B) = 0.25x*0.2 = 0.05x

What is the probability that a middle-aged man with diabetes is very active?

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.05x}{0.85x} = \frac{0.05}{0.85} = 0.0588

0.0588 = 5.88% probability that a middle-aged man with diabetes is very active

4 0
2 years ago
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Answer:

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