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DanielleElmas [232]

2 years ago

7

QUICK FIRST GETS BRAINLIEST!!!!! Use the interactive spinner to model who among Elisondra and her three friends will order first

.
Then answer the questions:

What is the theoretical probability of the spinner landing on Elisondra’s section?

Spin the spinner.

Who orders first?

2 answers:

katen-ka-za [31]2 years ago

7 0

Answer:

It depends if Elisondra and her friend's share of the wheel is the same but if it is the same, then it is a 1/4 chance because there are 4 people.

qwelly [4]2 years ago

6 0

Answer: The chance of Elisondra getting picked is 25%

Step-by-step explanation:

Now you spin the spinner and whoever it lands on is the one who orders first.

Good Luck!

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Answer:

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Step-by-step explanation:

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6 0

2 years ago

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A random draw is being designed for 210 participants. A single winner is to be chosen, and all the participants must have an equ

Over [174]

Answer: The correct number of balls is (b) 4.

Step-by-step explanation: Given that a single winner is to be chosen in a random draw designed for 210 participants. Also, there is an equal probability of winning for each participant.

We are using 10 balls, numbered through 0 to 9. We are to find the number of balls which needs to be picked up, regardless of order, so that each of the 210 participants can be assigned a unique set of numbers.

Let 'r' represents the number of balls to be picked up.

Since we are choosing from 10 balls, so we must have

$^{10}C_r=210.$

The value of 'r' can be any one of 0, 1, 2, . . , 10.

Now,

if r = 1, then

$^{10}C_1=\dfrac{10!}{1!(10-1)!}=\dfrac{10!}{1!9!}=\dfrac{10\times 9!}{1\times 9!}=10$

If r = 2, then

$^{10}C_2=\dfrac{10!}{2!(10-2)!}=\dfrac{10!}{2!8!}=\dfrac{10\times 9\times 8!}{2\times 1\times 8!}=45$

If r = 3, then

$^{10}C_3=\dfrac{10!}{3!(10-3)!}=\dfrac{10!}{3!7!}=\dfrac{10\times 9\times 8\times 7!}{3\times 2\times 1\times 7!}=120$

If r = 4, then

$^{10}C_4=\dfrac{10!}{4!(10-4)!}=\dfrac{10!}{4!6!}=\dfrac{10\times 9\times 8\times\times 7\times 6!}{4\times 3\times 2\times 1\times 6!}=210.$

Therefore, we need to pick 4 balls so that each participant can be assigned a unique set of numbers.

Thus, (b) is the correct option.

4 0

2 years ago

Read 2 more answers

goblinko [34]

Answer:

coordinate of point A is (a,b)

coordinate of point C is (2c,d)

slope of AD and BC = $\frac{b}{a-c}$

Step-by-step explanation:

According to midpoint formula

If we have points P $(x_{1} ,y_{1} )$ and Q $(x_{2} ,y_{2} )$

then the coordinate (x,y) of mid point of line PQ is given by

$x=\frac{x_{1} +x_{2} }{2}$ and $y=\frac{y_{1} +y_{2} }{2}$

now from the given diagram A is the mid point of line joining R(0,0) and S(2a,2b)

Using midpoint formula, coordinates of point A is given by

$x=\frac{0+2a}{2}= a$ and $y=\frac{0+2b}{2} =b$

so we have

coordinate of point A is (a,b)

Also C is the midpoint of line joining T (2c,2d) and V(2c,0)

coordinate of point C is given by

$x= \frac{2c+2c}{2} =2c$ and $y=\frac{2d+0}{2} =d$

so we have

coordinate of point C is (2c,d)

it is given that coordinate of point B is (a+c, b+d) and coordinate of D is (c,0)

If we have points P $(x_{1} ,y_{1} )$ and Q $(x_{2} ,y_{2} )$

then the slope of PQ = $\frac{y_{2} -y_{1} }{x_{2}-x_{1} }$

hence slope of AD= $\frac{0-b }{c-a}$

= $\frac{-b}{c-a}$

= $\frac{-b}{-(a-c)}$

= $\frac{b}{a-c}$

and slope of BC = $\frac{d-(b+d)}{2c-(a+c)}$

= $\frac{d-b-d}{2c-a-c}$

= $\frac{-b}{c-a}$

= $\frac{b}{a-c}$

so we have

slope of AD and BC = $\frac{b}{a-c}$

7 0

2 years ago

Read 2 more answers