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Alenkasestr [34]
2 years ago
5

1- find the first term= ?, 90, 540, 3240

Mathematics
1 answer:
Luda [366]2 years ago
4 0

Answer:

1. 15

2. 8

Step-by-step explanation:

The two sequence are geometric progression GP, because they follow a constant multiple (common ratio)

The nth term of a GP is;

Tn = ar^(n-1)

Where;

a = first term

r = common ratio

For the first sequence;

The common ratio r is

r = T3/T2 = 540/90 = 6

r = 6

T2 = ar^(2-1) = ar

T2 = 90 = ar

Substituting the values of r;

90 = a × 6

a = 90/6

a = 15

First term = 15

2. The sam method applies here.

Common ratio r = T3/T2 = 128/32 = 4

r = 4

T2 = ar^(2-1) = ar

T2 = 32 = ar

Substituting the values of r;

32 = a × 4

a = 32/4

a = 8

First term = 8

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defon

Answer:

1. Take the Average of the distances the ball travelled each hit.

2. He should use the Interquartile Range. This is the difference between the Upper Quartile and the Lower Quartile of the distances he hits the ball.

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4. He should use Median. It best measures skewed data

Step-by-step explanation:

THE FIRST PART.

Raul should take the average of the distances the ball travelled each hit.

This is done by summing the total distances the ball travelled each bounce, and then dividing the resulting value by the total number of times he hit the ball, which is 10.

THE SECOND PART

He should use the Interquartile Range. This is the difference between the Upper Quartile and the Lower Quartile of the distances he hits the ball.

THE THIRD PART

He should take the mean of the distances of the ball that stayed infield.

This is the distance that occurred the most during the 9 bounces that stayed infield. The one that went outfield is makes it unfair to use any other measure of the center, taking the mean will give a value that is significantly below his efforts.

THE FOURTH PART

He should take the Median of the data, it is best for skewed data.

This is the middle value for all the distances he recorded.

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2 years ago
A tailor cuts a piece of thread One-half of an inch long from a piece Nine-sixteenths of an inch long. What is the length of the
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Answer:

The length of the remaining piece of thread is  \frac{1}{16}.

Step-by-step explanation:

Given:

A tailor cuts a piece of thread One-half of an inch long from a piece Nine-sixteenths of an inch long.

Now, to find the length of the remaining piece of thread.

Total thread  = \frac{9}{16} \ inch.

Tailor cuts a piece of thread = \frac{1}{2}\ inch.  

Now, to get the length of the remaining piece of thread by subtracting tailor cuts a piece of thread from the total thread:

\frac{9}{16} -\frac{1}{2} \\\\=\frac{9-8}{16} \\\\=\frac{1}{16}

Therefore, the length of the remaining piece of thread is  \frac{1}{16}.

8 0
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A 1500 kg hippo is completely submerged, standing on the bottom of a lake. What is the approximate value of the upward normal fo
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Answer:

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Step-by-step explanation:

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V = 1,500 ÷ 1,030  = 1.46 m^3.

Buoyant force = Density * g * V  

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Net force = 14,700 – [(9,800 * (1,500 ÷ 1,030)]

7 0
2 years ago
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