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melamori03 [73]
2 years ago
14

The vertices of a parallelogram are A(x1, y1), B(x2, y2), C(x3, y3), and D(x4, y4). Which of the following must be true if paral

lelogram ABCD is proven to be a rectangle?

Mathematics
1 answer:
myrzilka [38]2 years ago
5 0

Answer:

Option 3.

Step-by-step explanation:

A parallelogram is said to be a rectangle if

1. Opposite pair of lines are equal and parallel

2. Adjacent lines meet each other at 90 degrees.

Hence we have third option which satisfies both the conditions.

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Suppose again that we are counting the ways to distribute exams to TAs and it matters which students' exams go to which TAs. The
abruzzese [7]

The question is incorrect.

The correct question is:

Three TAs are grading a final exam.

There are a total of 60 exams to grade.

(c) Suppose again that we are counting the ways to distribute exams to TAs and it matters which students' exams go to which TAs. The TAs grade at different rates, so the first TA will grade 25 exams, the second TA will grade 20 exams and the third TA will grade 15 exams. How many ways are there to distribute the exams?

Answer: 60!/(25!20!15!)

Step-by-step explanation:

The number of ways of arranging n unlike objects in a line is n! that is ‘n factorial’

n! = n × (n – 1) × (n – 2) ×…× 3 × 2 × 1

The number of ways of arranging n objects where p of one type are alike, q of a second type are alike, r of a third type are alike is given as:

n!/p! q! r!

Therefore,

The answer is 60!/25!20!15!

6 0
2 years ago
For the level 3 course, exam hours cost twice as much as workshop hours, workshop hours cost twice as much as lecture hours. How
natulia [17]
<h2>Answer</h2>

Cost of lectures = $7.33 per hour

<h2>Explanation</h2>

Let e the cost of the exam hours

Let w be the cost of the workshop hours

Let l be the cost of the lecture hours.

We know from our problem that exam hours cost twice as much as workshop, so:

e=2w equation (1)

We also know that workshop hours cost twice as much as lecture hours, so:

w=2l equation (2)

Finally, we also know that 3hr exams 24hr workshops  and 12hr lectures cost $528, so:

3e+24w+12l=528 equation (1)

Now, lets find the value of l:

Step 1.  Solve for l in equation (3)

3e+24w+12l=528

12l=528-3e-24w equation (4)

Step 2. Replace equation (1) in equation (4) and simplify

12l=528-3e-24w

12l=528-3(2w)-24w

12l=528-6w-24w

12l=528-30w equation (5)

Step 3. Replace equation (2) in equation (5) and solve for l

12l=528-30w

12l=528-30(2l)

12l=528-60l

72l=528

l=\frac{528}{72}

l=\frac{22}{3}

l=7.33

Cost of lectures  = $7.33 per hour



3 0
2 years ago
Read 2 more answers
Fruit juice comes in two types of containers. The first is a rectangular prism that is 9 inches tall and has a rectangular base
My name is Ann [436]

The volume of a rectangular prism:

V_p=Bh\\\\B=wl\\\\w=2\ in;\ l=3\ in;\ h=9\ in

substitute

V_p=2\cdot3\cdot9=54\ in^3

The volume of a cylinder:

V_c=\pi r^2h\\\\r=1.5\ in;\ h=8\ in

substitute:

V_c=\pi\cdot(1.5)^2\cdot8=\pi\cdot2.25\cdot8=18\pi\ in^3\approx18\cdot3.14=56.52\ in^3

Answer: C. The cylinder has the greater volume.

3 0
2 years ago
I need help please help me
Lostsunrise [7]

Answer:

which one do you need help on

6 0
2 years ago
Find the area of a regular polygon
Dimas [21]

Answer:

(N-2)x180=sum of interior angles

So (5-2)x180=540

Divided by number of sides=540/4=108... then each angle is 108 divide to triangles ..so they will have 2 angles =54 2 sides =4 the last angle =72 ."of the triangle " area of triangle =1/2xsxsxsin(side in

between)

So 1/2x4x4xsin(72)= then multiply it by 5 as u will have 5 triangles .. so it will be 190.2(probably i tried)

Step-by-step explanation:

4 0
2 years ago
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