Answer: Barbarino's rentals has a better deal.
She has to drive 887.5 miles to spend the same amount at either company.
Step-by-step explanation:
Hi, to answer this question we have to analyze the information given:
<em>Mr.kotters rentals (A)
</em>
- <em>$99 PER WEEK
</em>
- <em>$0.11per mile over 100 miles
</em>
<em>Barbarino's rentals (B)
</em>
- <em>$75 per week
</em>
- <em>$0.15 per mile over 150 miles
</em>
For "A"
Cost = 0.11 (432-100) + 99 = $135.52
For "B"
Cost= 0.15 (432-150) +75 = $117.3
Barbarino's rentals has a better deal, since $117.3(B) < $135.52 (A)
To find how many miles would Glenna drive before she would be spending the same amount at either company:
A =B
0.11 (M-100) + 99 =0.15 (M-150) +75 = $117.3
Solving for M (miles)
0.11 M -11+99 = 0.15 M -22.5+75
-11 +99 +22.5 -75 =0.15M -0.11 M
35.5 = 0.04M
35.5/0.04 = M
887.5 =M
She has to drive 887.5 miles to spend the same amount at either company.
Answer: C) For every original price, there is exactly one sale price.
For any function, we always have any input go to exactly one output. The original price is the input while the output is the sale price. If we had an original price of say $100, and two sale prices of $90 and $80, then the question would be "which is the true sale price?" and it would be ambiguous. This is one example of how useful it is to have one output for any input. The input in question must be in the domain.
As the table shows, we do not have any repeated original prices leading to different sale prices.
Answer:
2
Step-by-step explanation:
C is too small to have more.
Answer:
A. $301
B. $721
Step-by-step explanation:
Let $x be the amount of money they raised.
Rowena tried to put the $1 bills into two equal piles and found one left over at the end, then
Polly tried to put the $1 bills into three equal piles and found one left over at the end, then
Frustrated, they tried 4, 5, and 6 equal piles and each time had $1 left over, then
Finally Rowena put all the bills evenly into 7 equal piles, and none were left over, then
This means 
is divisible by 2, 3, 4, 5 and 6 without remainder, so
Hence,
The smallest amount of money they could have raised is $301, because
is divisible by 7.
Now, the number 
should be divisible by 7 and must be greater than 500.
So,
When n = 9,
is not divisible by 7.
When n = 10,
is not divisible by 7.
When n = 11,
is not divisible by 7.
When n = 12,
is divisible by 7.
B. The least amount of money they could have raised is $721
Answer:
9×10,000+4×10 eauals to 90,040
