<span>(x) - (0.03)(200) = 2.00
Let x be the </span><span>company charge to make the profit
solving for x gives 8$</span>
Answer:
<em>Mean of the sample = 27.83</em>
<em> The variance of the the sample = 106.96</em>
<em> </em><em>Standard deviation of the sample = 10.34</em>
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given random sample of six employees
x 26 32 29 16 45 19
mean of the sample
Mean of the given data = 27.83
<u>Step(ii):-</u>
<u>Given data</u>
x : 26 32 29 16 45 19
x - x⁻ : -1.83 4.17 1.17 -11.83 17.17 -8.83
(x - x⁻)² : 3.3489 17.3889 1.3689 139.9489 294.80 77.9689
∑ (x-x⁻)² = 534.8245
Given sample size 'n' =6
The variance of given data
S² = ∑(x-x⁻)² / n-1
The variance of the given sample = 106.9649
<u> Step(iii):-</u>
Standard deviation of the given data
Standard deviation of the sample = 10.3423
To solve this problem you must follow the proccedure shown below:
1. Amount of lemonade in pints:
1 <span>quart of water=2 pints
1 pint of lemon
(9 ounces of honey)(0.0625 pints/1 ounce)=0.56 pints
Total in pints=2 pints+1 pint+0.56 pints
Total in pints=3.56 pints
2. </span>Amount of lemonade in<span> cups:
Total in cups=(3.56 pints)(2 cups/1 pint)
Total in cups=7.12 cups
3. </span>Amount of lemonade in<span> ounces:
Total in ounces=(7.12 cups)(8 ounces/1 cup)
Total in ounces=56.96 ounces</span>
Answer:
a.0.8664
b. 0.23753
c. 0.15866
Step-by-step explanation:
The comptroller takes a random sample of 36 of the account balances and calculates the standard deviation to be N42.00. If the actual mean (1) of the account balances is N175.00, what is the probability that the sample mean would be between
a. N164.50 and N185.50?
b. greater than N180.00?
c. less than N168.00?
We solve the above question using z score formula
z = (x-μ)/σ/√n where
x is the raw score,
μ is the population mean = N175
σ is the population standard deviation = N42
n is random number of sample = 36
a. Between N164.50 and N185.50?
For x = N 164.50
z = 164.50 - 175/42 /√36
z = -1.5
Probability value from Z-Table:
P(x = 164.50) = 0.066807
For x = N185.50
z = 185.50 - 175/42 /√36
z =1.5
Probability value from Z-Table:
P(x=185.50) = 0.93319
Hence:
P(x = 185.50) - P(x =164.50)
= 0.93319 - 0.066807
= 0.866383
Approximately = 0.8664
b. greater than N180.00?
x > N 180
Hence:
z = 180 - 175/42 /√36
z = 5/42/6
z = 5/7
= 0.71429
Probability value from Z-Table:
P(x<180) = 0.76247
P(x>180) = 1 - P(x<180) = 0.23753
c. less than N168.00?
x < N168.
z = 168 - 175/42 /√36
z = -7/42/6
z = -7/7
z = -1
Probability value from Z-Table:
P(x<168) = 0.15866
the answer should be 780π
