Answer:
48.6
Step-by-step explanation:
If you use 8.1g of sugar for 1 cake then 6 cakes will be 48.6g of sugar
Just do 8.1*6 and you will get 48.6
Given the function f (x) = 3x, find the value of f-1 (81).
For this case, the first thing you should do is rewrite the function.
We have then:
y = 3 ^ x
From here, we clear the value of x:
log3 (y) = log3 (3 ^ x)
log3 (y) = x
Then, we rewrite the function again:
f (x) ^ - 1 = log3 (x)
Now, we evaluate the inverse function for x = 81:
f (81) ^ - 1 = log3 (81)
f (x) ^ - 1 = 4
Answer:
the value of f-1 (81) is:
f (x) ^ - 1 = 4
Answer:
y''=-1.26
Step-by-step explanation:
We are given that 
We have evaluate the second order derivative of y w.r.t. x when x=2 and y=3.
Differentiate w.r.t x
Then , we get
Again differentiate w.r.t.x
Then , we get
Using value of y'
Substitute x=2 and y=3
Then, we get 
Hence,y''=-1.26
Answer: In the beginning he was given 27 sweets.
Step-by-step explanation: The most logical thing to do is to solve it backwards, that is, from what he had at the end of the third day up till the beginning of the first day.
On the third day he ate one-third and had 8 sweets left over. To determine how many he started with on the third day, let the total on day three be called a. If one-third of a is eaten, then the left over which is two-thirds is 8. That is;
8/a = 2/3
By cross multiplication we now have
8 x 3 = 2a
24/2 = a
a = 12
Let the number of sweets he had on day two be called b. If he ate one-third of b and he had 12 left over, then the two-thirds left over is 12 and we now have;
12/b = 2/3
By cross multiplication we now have
12 x 3 = 2b
36 = 2b
36/2 = b
b = 18
Let the number of sweets he had on day one be called x. If he ate one-third of x and he had 18 left over, then the two-thirds left over is 18, and we now have;
18/x = 2/3
By cross multiplication we now have
18 x 3 = 2x
54 = 2x
x = 27
Therefore Tim was given 27 sweets at the beginning.
