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Natali5045456 [20]

2 years ago

9

One option in a roulette game is to bet $2 on red. (There are 18 red compartments, 18 black compartments, and two compartmen

ts that are neither red nor black.) If the ball lands on red, you get to keep the $2 you paid to play the game and you are awarded $2. If the ball lands elsewhere, you are awarded nothing and the $2 that you bet is collected. Find the expected payback for this roulette game if you bet $2 on red.

1 answer:

aleksandrvk [35]2 years ago

4 0

It cost $46.000 for the red.

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If bd = 7x-10, bc = 4x-29, and cd = 5x-9, find each value

Airida [17]

Answer:

$bd=88$ , $bc=27$ , $cd=61$

Step-by-step explanation:

In this problem we have that

$bd=bc+cd$

we have

$bd=7x-10$

$bc=4x-29$

$cd=5x-9$

substitute the values and solve for x

$7x-10=(4x-29)+(5x-9)$

Group terms that contain the same variable in the right sides

$7x-10=(4x+5x)+(-29-9)$

Combine like terms in the right side

$7x-10=9x-38$

$9x-7x=-10+38$

$2x=28$

$x=14$

<u><em>Find the value of bd</em></u>

$bd=7(14)-10=88$

Find the value of bc

$bc=4(14)-29=27$

<u><em>Find the value of cd</em></u>

$cd=5(14)-9=61$

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2 years ago

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miss Akunina [59]

The correct answers are:

1. f (x) is translated 4 units down.

2. f (x) is vertically stretched by a factor of 4.

I took the quiz and these were the right answers. Hope I helped! <3

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2 years ago

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The length of a swimming pool is 8m longer than its width and the area is 105m2

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$width : w \\ length : \ l = w + 8 \\ A = 105 \ m^2 \\ \\A= w \cdot l \\ \\w(w+l)=105 \\ \\w^2+w = 105 \\ \\w^2+w-105 =0 \\ \\(w+15)(w-7)=0 \\ \\w+15 =0 \ \ or \ \ w-7 = 0 \\ \\w = -15 \ \ or \ \ w=7 \\ \\ width \ cant \ be \ negative, \ so \\ \\ w = 7 \ and \ l = w+8 = 7 +8 =15 \\ \\chek : \\ \\ A=w\cdot l \\ \\A=7\cdot 15=105 \ m^2$

8 0

1 year ago

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24. ABCDE and PQRST are regular pentagons.

SIZIF [17.4K]

Answer:

126°

Step-by-step explanation:

In quadrilateral DSRC, SR || DC (given)

AP = BQ = CR = DS = ET (given)

$\therefore$ CR bisects $\angle DCB$

$\therefore m\angle DCR=\frac{108\degree}{2}$

( $108\degree$ is the measure of an angle of pentagon)

$\therefore m\angle DCR=54\degree$

$\because m\angle DCR + m\angle SRC=180\degree$

(Measure of interior angles on the same side of transversal)

$\therefore 54\degree + m\angle SRC=180\degree$

$\therefore m\angle SRC=180\degree- 54\degree$

$\therefore m\angle SRC=126\degree$

3 0

2 years ago

An urn contains 3 red and 7 black balls. Players and withdraw balls from the urn consecutively until a red ball is selected. Fin

Sliva [168]

Correct question:

An urn contains 3 red and 7 black balls. Players A and B withdraw balls from the urn consecutively until a red ball is selected. Find the probability that A selects the red ball. (A draws the first ball, then B, and so on. There is no replacement of the balls drawn).

Answer:

The probability that A selects the red ball is 58.33 %

Step-by-step explanation:

A selects the red ball if the first red ball is drawn 1st, 3rd, 5th or 7th

1st selection: 9C2

3rd selection: 7C2

5th selection: 5C2

7th selection: 3C2

9C2 = (9!) / (7!2!) = 36

7C2 = (7!) / (5!2!) = 21

5C2 = (5!) / (3!2!) = 10

3C2 = (3!) / (2!) = 3

sum of all the possible events = 36 + 21 + 10 + 3 = 70

Total possible outcome of selecting the red ball = 10C3

10C3 = (10!) / (7!3!)

= 120

The probability that A selects the red ball is sum of all the possible events divided by the total possible outcome.

P( A selects the red ball) = 70 / 120

= 0.5833

= 58.33 %

7 0

2 years ago