Answer:
In Right Δ ABC with right angle B,
∠A=(3 x -8)°, ∠B=90°, ∠C=(x-2)°
∠A+∠B+∠C=180°[∠ sum property of triangle]
3 x-8+90 + x-2=180
Adding and subtracting like terms
4 x-10+90=180
4 x+80=180
4 x=180-80
4 x=100
x=100/4
x=25°
∠A=3×25-8=75-8=67°
For this case we have:
Polynomial 1: 
Polynomial 2: 
Sorting the polynomials:
Polynomial 1: 
Polynomial 2: 
Adding term to term (similar) we have:

Answer:

There was 3000 general admission tickets sold and 500 kid ticket sold.
How did I get this?
First, we need to see what information we have.
$2.50 = General admission tickets = (G)
$0.50 = kids tickets = (K)
There were 6x as many general admission tickets sold as kids. G = 6K
We need two equations:
G = 6K
$2.50G + $.50K = $7750
Since, G = 6K we can substitute that into the 2nd equation.
2.50(6K) + .50K = 7750
Distribute 2.50 into the parenthesis
15K + .50K = 7750
combine like terms
15.50K = 7750
Divide both sides by 15.50, the left side will cancel out.
K = 7750/15.50
K = 500 tickets
So, 500 kid tickets were sold.
Plug K into our first equation (G = 6k)
G = 6*500
G = 3000 tickets
So, 3000 general admission tickets were sold,
Let's check this:
$2.50(3000 tickets) = $7500 (cost of general admission tickets)
$.50(500 tickets) = $250 (cost of general admission tickets)
$7500 + $250 = $7750 (total cost of tickets)
First we need to find the heigh of the soda can be rearanging the volume formula,

. We can make that

We know that V is 36 and radius is half of the diameter, so radius is 2.


h = 2.87
Now, we can use the height to figure out the volume of a cone. The volume of a cone is

R is 2 again and h is 2.87


12.56*.96 = 12.0576
So a cone with a volume of 12.0576 is the largest that will fit into the soda can