Denise is constructing A square.
Note: A square has all sides equal.
We already given two vertices M and N of the square.
And another edge of the square is made by from N.
Because a square has all sides of equal length, the side NO should also be equal to MN side of the square.
Therefore, <em>Denise need to place the point of the compass on point N and draw an arc that intersects N O, using MN as the width for the opening of the compass. That would make the NO equals MN.</em>
Therefore, correct option is :
D) place the point of the compass on point N and draw an arc that intersects N O, using MN as the width for the opening of the compass.
We are given with
v1 = 5.5 km/hr
v2 = 4.5 km/hr
d = 10 km
v3 = 30 km/hr
The total time the fly was flying back and forth is
5.5t + 4.5t - 10
t = 1 hr
The total distance traveled by the fly is
d = 30 (1) = 30 km
Answer: the length of the extended ladder is 8√3 feet or 13.9 feet
the distance between the wall and the bottom of the ladder is 4√3 feet or 6.9 feet
Step-by-step explanation:
The ladder forms a right angle triangle with the building and the ground. The length of the ladder represents the hypotenuse of the right angle triangle. The height from the top of the ladder to the base of the building represents the opposite side of the right angle triangle.
The distance from the bottom of the ladder to the base of the building represents the adjacent side of the right angle triangle.
To determine the extended length of the ladder h, we would apply
the Sine trigonometric ratio.
Sin θ = opposite side/hypotenuse. Therefore,
Sin 60 = 12/h
√3/2 = 12/h
h = 12 × 2/√3 = 24√3
h = 24√3 × √3/√3
h = 8√3
To determine the distance between the wall and the bottom of the ladder d, we would apply
the cosine trigonometric ratio.
Cos θ = adjacent side/hypotenuse.
Therefore,
Cos 60 = d/8√3
0.5 = d/8√3
d = 0.5 × 8√3
d = 4√3
Step-by-step explanation:
Given precision is a standard deviation of s=1.8, n=12, target precision is a standard deviation of σ=1.2
The test hypothesis is
H_o:σ <=1.2
Ha:σ > 1.2
The test statistic is
chi square = 
=
=24.75
Given a=0.01, the critical value is chi square(with a=0.01, d_f=n-1=11)= 3.05 (check chi square table)
Since 24.75 > 3.05, we reject H_o.
So, we can conclude that her standard deviation is greater than the target.
