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Vadim26 [7]
2 years ago
9

Two horses approach each other along the same country road, one walking at 5.5 km/h and the other at 4.5 km/h. When the horses a

re 10 km apart, a horsefly leaves one horse and flies at 30 km/h to the other, No sooner does the fly reach that horse than it turns around and returns to the first horse. If the fly continues to fly back and forth between the approaching horses, how far has the fly flown when the horses meet?
Mathematics
1 answer:
lisov135 [29]2 years ago
4 0
We are given with
v1 = 5.5 km/hr
v2 = 4.5 km/hr
d = 10 km
v3 = 30 km/hr

The total time the fly was flying back and forth is
5.5t + 4.5t - 10
t = 1 hr

The total distance traveled by the fly is
d = 30 (1) = 30 km
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For circle O, and m∠ABC = 55°. In the figure, ∠_____ and ∠____ have measures equal to 35°.
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Answer:

In the figure ∠ABO and ∠BCO have measures equal to 35°.

Step-by-step explanation:

<u><em>The complete question is</em></u>

For circle O, m CD=125° and m∠ABC = 55°

In the figure<____, (AOB, ABO, BOA)  and <_____ (BCO, OBC,BOC) have measures equal to 35°

The picture in the attached figure

step 1

Find the measure of angle COB

we know that

m\angle COB=arc\ CD ----> by central angle

we have

arc\ CD=125^o

therefore

m\angle COB=125^o

step 2

we know that

AB is a tangent to the circle O at point A

so

ABC and ABO are right triangles

In the right triangle ABC

Find the measure of angle BCA

Remember that

m\angle BCA+m\angle\ ABC=90^o ---> by complementary angles in a right triangle

we have

m\angle ABC=55^o

substitute

m\angle BCA+55^o=90^o

m\angle BCA=90^o-55^o=35^o\\

step 3

In the triangle BCO

Find the measure of angle CBO

we know that

m\angle CBO+m\angle COB+m\angle BCO=180^o ---> the sum of the interior angles in any triangle must be equal to 180 degrees

we have

m\angle COB=125^o

m\angle BCO=m\angle BCA=35^o -----> have measure equal to 35 degrees

substitute

m\angle CBO+125^o+35^o=180^o

m\angle CBO=180^o-160^o=20^o

step 4

Find the measure of angle ABO

In the right triangle ABO

we know that

m\angle ABC=m\angle CBO+m\angle ABO ----> by angle addition postulate

we have

m\angle ABC=55^o

m\angle CBO=20^o

substitute

55^o=20^o+m\angle ABO

m\angle ABO=55^o-20^o=35^o ----> have measure equal to 35 degrees

therefore

In the figure ∠ABO and ∠BCO have measures equal to 35°.

3 0
2 years ago
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