Ask question

Ask question

All categories

anastassius [24]

2 years ago

10

What effect will a translation 3 units down and 2 units left have on the polygon? Be sure to address how it could impact the ang

les, side lengths, and congruency between the original pre-image and the image.

2 answers:

Tanzania [10]2 years ago

8 0

For the answer to the question above, when you carry your jewelry box or your phone 3 floors down
and 2 miles to the left, the angles and side lengths don't change,
and it still looks exactly the same as it did before you picked it up
and moved it.

Translation can't change angles or lengths. And if those don't
change, then the later shape is congruent to the earlier shape.

Nata [24]2 years ago

6 0

Answer:

For the answer to the question above, when you carry your jewelry box or your phone 3 floors down

and 2 miles to the left, the angles and side lengths don't change,

and it still looks exactly the same as it did before you picked it up

and moved it.

.

Step-by-step explanation:

You might be interested in

HELP PLEASE I NEEED HELP!!!!

Nina [5.8K]

It is d just trust me

4 0

2 years ago

The Bay Area Online Institute (BAOI) has set a guideline of 60 hours for the time it should take to complete an independent stud

yarga [219]

Answer:

At the 5% level, BAOI can infer that the average time to complete does not exceeds 60 hours.

Step-by-step explanation:

From the question we are told that

The population mean is $\mu = 60 \ hr$

The sample size is $n = 16$

The sample mean is $\= x = 68 \ hr$

The standard deviation is $\sigma = 20 \ hr$

The null hypothesis is $H_o : \mu = 60$

The alternative $H_a : \mu > 60$

Here we would assume the level of significance of this test to be

$\alpha = 5\% = 0.05$

Next we will obtain the critical value of the level of significance from the normal distribution table, the value is $Z_{0.05} = 1.645$

Generally the test statistics is mathematically represented as

$t = \frac{ \= x - \mu}{ \frac{ \sigma }{\sqrt{n} } }$

substituting values

$t = \frac{ 68 - 60 }{ \frac{ 20 }{\sqrt{16} } }$

$t = 1.6$

Looking at the value of t and $Z_{\alpha }$ we see that $t< Z_{\alpha }$ hence we fail to reject the null hypothesis

This means that there no sufficient evidence to conclude that it takes more than 60 hours to complete the course

So

At the 5% level, BAOI can infer that the average time to complete does not exceeds 60 hours.

6 0

1 year ago

A carpenter bought 4 boxes of nails. Each box weighed 3 and 2/5 pounds. The price of the nails was $8 per pound. How much did th

neonofarm [45]

Answer:

108.80

Step-by-step explanation:

8 0

2 years ago

Find the dimensions of the box with volume 1728 cm3 that has minimal surface area. (Let x, y, and z be the dimensions of the box

Gala2k [10]

Answer:

The dimensions of the box are 12 cm , 12 cm , 12 cm

Step-by-step explanation:

Let x , y and z be the dimensions of box

Volume of box =xyz=1728

$z=\frac{1728}{xy}$

Surface area of box = $2xy+2yz+2xz=2xy+2y(\frac{1728}{xy})+2x(\frac{1728}{xy})$

Let $f(x,y)=2xy+2(\frac{1728}{x})+2(\frac{1728}{y})$

To get minimal surface area

$\frac{\partial f}{\partial x}=0$ and $\frac{\partial f}{\partial y}=0$

$\frac{\partial(2xy+2(\frac{1728}{x})+2(\frac{1728}{y}))}{\partial x}=0$

$2y-2(\frac{1728}{x^2})=0$

$y=\frac{1728}{x^2}$ ----1

$\frac{\partial(2xy+2(\frac{1728}{x})+2(\frac{1728}{y}))}{\partial y}=0$

$2x-2(\frac{1728}{y^2})=0\\x=\frac{1728}{y^2} \\y^2=\frac{1728}{x}$

Using 1

$(\frac{1728}{x^2} )^2=\frac{1728}{x}$

x=0 and $x^3=1728$

Side can never be 0

So, $x^3=1728$

x=12

$y=\frac{1728}{x^2} \\y=\frac{1728}{12^2}$

y=12

$z=\frac{1728}{xy}\\z=\frac{1728}{(12)(12)}$

z=12

The dimensions of the box are 12 cm , 12 cm , 12 cm

5 0

2 years ago

The formula for the future value V (in dollars) of an investment earning simple interest is V=p+prt, where p (in dollars) is the

zhannawk [14.2K]

a)

V=p+prt

now we solve for P

V=P (1+rt)

Divide both sides by (1+rt)

P=V÷(1+rt)...answer

b)

P=V÷(1+rt)

P=3,000÷(1+0.06×5)

P=2,307.69

5 0

2 years ago