Hello,
I am going to remember:
y'+3y=0==>y=C*e^(-3t)
y'=C'*e^(-3t)-3C*e^(-3t)
y'+3y=C'*e^(-3t)-3Ce^(-3t)+3C*e^(-3t)=C'*e^(-3t) = t+e^(-2t)
==>C'=(t+e^(-2t))/e^(-3t)=t*e^(3t)+e^t
==>C=e^t+t*e^(3t) /3-e^(3t)/9
==>y= (e^t+t*e^(3t)/3-e^(3t)/9)*e^(-3t)+D
==>y=e^(-2t)+t/3-1/9+D
==>y=e^(-2t)+t/3+k
Answer:
7/11 of the Pizza was left for Zachary.
Step-by-step explanation:
Zachary had 1 - 4/11
= 11/11 - 4 /11
= 7/11.
sandbox 1 area = 5*5 = 25 square m
sandbox 2
25=w*(3w+1)=
3w^2+w-25=0
w=2.7248 (round to 2.72 m)
2.72*3=8.16+1 = 9.16
Longest side = 9.16 meters
Answer: 
Mustafa could have written more than 8 articles for the newspaper.
Step-by-step explanation:
Given: Heloise has written 1/4 as many articles as Mustafa has. Gia has written 3/2 as many articles as Mustafa has.
Let m be the number of articles Mustafa writes.
Then articles written by Heloise=
And articles written by Gia=
The total number of articles =
Mustafa, Heloise, and Gia have written more than a combined total of 22 articles for the school newspaper.
Hence, Mustafa could have written more than 8 articles for the newspaper.
A^2 + 5^2 = 10^2
a^2 + 25 = 100
a^2 = 100-25
a^2 = 75
a = sqrt(75) = 5sqrt(3)
answer is A