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2 years ago

Yuna's favorite type of cheese crackers has 30 crackers for each serving.

Mathematics

1 answer:

Yuliya22 [10]2 years ago

7 0

Answer:

1 serving is 30 crackers

2 servings is 60 crackers

3 servings is 90 crackers

4 servings is 120 crackers

5 servings is 150 crackers.

Step-by-step explanation:

To find out how many crackers for how many servings you multiply one serving (30 crackers) by the amount of servings.

Example:

1 serving 30 × 1 = 30

2 servings 30 × 2 = 60

3 servings 30 × 3 = 90

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The box plots compare the number of students in Mr. Ishimoto’s classes and in Ms. Castillo’s classes over the last two semesters

Ilya [14]

-Both box plots show the same interquartile range.
>Interquartile range (IQR) is computed by Q3-Q1.
For Mr. Ishimoto's class, Q3 is 35 and Q1 is 31. 35-31 = 4.
For Ms. Castillo's class, Q3 is 34 and Q1 is 30. 34-30 = 4.

-Mr. Ishimoto had the class with the greatest number of students.
>Mr. Ishimoto had 40 students, represented by the last data point of the whiskers.

-The smallest class size was 24 students.
>Which was Ms. Castillo's class.

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2 years ago

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Assume that Mrs. Giang’s car travels 14 miles on each gallon of gas. If she travels to visit her niece who lives 133 miles away,

frutty [35]

Take the amount 14 MPG (miles per gallon)

Then take the number of miles to go (133 miles to go)

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133/14
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2 years ago

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The amount of time it takes for a student to complete a statistics quiz is uniformly distributed (or, given by a random variable

topjm [15]

Answer:

(A) 0.15625

(B) 0.1875

(C) Can't be computed

Step-by-step explanation:

We are given that the amount of time it takes for a student to complete a statistics quiz is uniformly distributed between 32 and 64 minutes.

Let X = Amount of time taken by student to complete a statistics quiz

So, X ~ U(32 , 64)

The PDF of uniform distribution is given by;

f(X) = $\frac{1}{b-a}$ , a < X < b where a = 32 and b = 64

The CDF of Uniform distribution is P(X <= x) = $\frac{x-a}{b-a}$

(A) Probability that student requires more than 59 minutes to complete the quiz = P(X > 59)

P(X > 59) = 1 - P(X <= 59) = 1 - $\frac{x-a}{b-a}$ = 1 - $\frac{59-32}{64-32}$ = $1-\frac{27}{32}$ = 0.15625

(B) Probability that student completes the quiz in a time between 37 and 43 minutes = P(37 <= X <= 43) = P(X <= 43) - P(X < 37)

P(X <= 43) = $\frac{43-32}{64-32}$ = $\frac{11}{32}$ = 0.34375

P(X < 37) = $\frac{37-32}{64-32}$ = $\frac{5}{32}$ = 0.15625

P(37 <= X <= 43) = 0.34375 - 0.15625 = 0.1875

= P(X = 44.74)

The above probability can't be computed because this is a continuous distribution and it can't give point wise probability.

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2 years ago

Pete corporation produces bags of peanuts. It's fixed cost is $18,900. Each bag sells for $2.17 with a unit cost of $1.27. What

pentagon [3]

Answer:

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